You want something like this:

 	<xs:element name="Foo">
		<xs:complexType>
               <xs:simpleContent>
                 <xs:restriction base="xs:token">
  			<xs:enumeration value="ABC" />
  			<xs:enumeration value="123" />
  			<xs:enumeration value="DEF" />
  		     </xs:restriction> 			 
               </xs:simpleContent>
               <xs:attribute name="_Code" type="xs:string"/>
 		</xs:complexType>
 	</xs:element>

ALternatively you can define the type of Foo as an extension of FooType
(extended by adding an attribute)

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: xmlschema-dev-request@w... 
> [mailto:xmlschema-dev-request@w...] On Behalf Of Fortuno, Adam
> Sent: 15 December 2006 19:26
> To: xmlschema-dev@w...
> Subject: Element Takes Enumerated List but has Attribute that 
> Takes a String
> 
> 
> All,
> 
> I'm trying to create the below structure
> 
> <Foo _Code="XYZ">ABC</Foo>
> 
> Where the element `Foo` takes a literal value from an 
> enumerated list, and the attribute `_Code` takes a 
> (xs:)string. I have tried a few different constructs based on 
> research I've done. I can get the enumerated list for the 
> element but not the attribute or vice versa. 
> 
> Any suggestions would be appreciated. Here is what I've tried 
> (doesn't work).
> 
> 	<xs:element name="Foo" type="FooType">
> 		<xs:complexType>
> 			 <xs:attribute name="_Code" type="xs:string"/>
> 		</xs:complexType>
> 	</xs:element>
> 	 <xs:simpleType name="FooType">
> 		<xs:restriction base="xs:token">
> 			<xs:enumeration value="ABC" />
> 			<xs:enumeration value="123" />
> 			<xs:enumeration value="DEF" />
> 		</xs:restriction>
> 	 </xs:simpleType>
> 
> Regards,
> Adam
> 
> 


From noah_mendelsohn@u... Tue Dec 19 15:11:04 2006
Received: from maggie.w3.org ([193.51.208.