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RE: NewBie Question

From: =?iso-8859-1?Q?H=E4mmer_Wolfgang?= <Wolfgang.Haemmer@---.--->
To: "George Cristian Bina" <george@---------.--->
Date: 6/23/2005 12:45:00 PM
Salut George,

Thank you for your help!

The problem with this solution is that I do not know in advance what the =
name of the element will be. I would like ot be able to write ...

Expect an element x of type CommonType of unknown name.

Best regards, Wolf

-----Original Message-----
From: George Cristian Bina [mailto:george@o...]
Sent: Donnerstag, 23. Juni 2005 10:06
To: H=E4mmer Wolfgang
Cc: xmlschema-dev@w...
Subject: Re: NewBie Question


Hi Wolf,

You can reuse a type in XML schema if you define that is a global type 
definition and then set that type to the elements that you want to have 
the same content. Something like below:

<xs:complexType name="CommonType" mixed="true">
     <xs:sequence>
         <xs:element name="LocalVariables" minOccurs="1" =
maxOccurs="1">
             <xs:complexType>
                 <xs:choice>
                     <xs:sequence>
                         <xs:element name="l_start" minOccurs="1" 
maxOccurs="1"/>
                         <xs:element name="l_end" minOccurs="1" 
maxOccurs="1"/>
                     </xs:sequence>
                     <xs:sequence>
                         <xs:element name="l_first" minOccurs="1" 
maxOccurs="1"/>
                         <xs:element name="l_second" minOccurs="1" 
maxOccurs="1"/>
                         <xs:element name="l_third" minOccurs="1" 
maxOccurs="1"/>
                     </xs:sequence>
                 </xs:choice>
             </xs:complexType>
         </xs:element>
     </xs:sequence>
</xs:complexType>
<xs:element name="TableDrop" type="CommonType"/>
<xs:element name="Sizes" type="CommonType"/>

Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
www.---.com


H=E4mmer Wolfgang wrote:
> Hello,
> 
> this is something I wanted to ask for a long time ....
> 
> 
> Is there a way using a xml schema to describe an element which name =
changes as in ...
> 
> 			<TableDrop>
> 				public string code (string l_p) { 
> 					return l_first + l_p + l_second + l_p + l_third;
> 				}=09
> 				<LocalVariables>
> 					<l_first>
>    						 aString =  _T(&quot;drop table </l_first>
> 					<l_second>
> 						&quot;); hr = Oc.Execute( aString );
>    						 if ( FAILED(hr) ) _tprintf(_T(&quot;Oc.Execute drop table =
failed with EBSc_TAB_</l_second>
> 					<l_third>
> 						&quot;));
> 					</l_third>
> 				</LocalVariables>
> 			</TableDrop>
> 			<Sizes>
> 				public string code (string l_p) { return l_start + l_p + l_end;}
> 				<LocalVariables>
> 					<l_start>//TYPEDEF[attribute::name=</l_start>
> 					<l_end>]/attribute::size</l_end>
> 				</LocalVariables>
> 			</Sizes>
> 
> The elements TableDrop and Sizes have the same structure but bear =
different names.
> 
> I would like to write something like ....
> 
> 	<xs:element name='.*'>
>      	<xs:complexType>
>                <xs:sequence>
>           		<xs:element name="LocalVariables" minOccurs="1" =
maxOccurs="1">
> 			     	<xs:complexType>
>                			<xs:sequence>
>           					<xs:element name="l_start" minOccurs="1" =
maxOccurs="1">
>           					<xs:element name="l_end" minOccurs="1" =
maxOccurs="1">
> 			               <xs:sequence>
> 					</xs:complexType>
> 				</xs:element>
>                <xs:sequence>
> 		</xs:complexType>
> 	</xs:element>
> 
> Thanks for your help!
> 
> Kind regards, Wolf
>  
>  
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From george@o... Thu Jun 23 08:54:03 2005
Received: from bart.w3.org ([128.30.52.40])
	by frink.w3.org with esmtp (Exim 4.50)
	id 1DlNTH-0004Dd-5Z
	for xmlschema-dev


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