http://www.altova.com/ Altova accelerates application development and data management projects with software and solutions that enhance productivity and maximize results. As an innovative, customer-focused company and the creator of XMLSpy and other leading XML, data administration, UML, and Web services tools, Altova is the choice of over 3 million clients worldwide, including virtually every Fortune 500 company. With customers ranging from vast development teams in the world’s largest organizations to progressive one-person shops, Altova’s line of software applications fulfills a broad spectrum of business needs. Altova is an active member of the World Wide Web Consortium (W3C) and Object Management Group (OMG) and is committed to delivering standards-based platform-independent solutions that are powerful, affordable, and easy to use. Altova was founded in 1992 and has headquarters in Beverly, Massachusetts and Vienna, Austria. en-us Copyright © 2005, 2006, 2007 Altova GmbH. All rights reserved. Altova, XMLSpy, MapForce, StyleVision, SemanticWorks, SchemaAgent, UModel, DiffDog, and Authentic are trademarks and/or registered trademarks of Altova GmbH in the United States and/or other countries. The names of and reference to other companies and products mentioned herein may be the trademarks of their respective owners. Tue, 03 Jun 2008 10:00:00 EDT Tue, 03 Jun 2008 10:00:00 EDT Authentic RSS Editor, visit www.altova.com for details pr@altova.com webmaster@altova.com http://www.altova.com/images/logos/altova_right_120.gif http://www.altova.com/ 120 24 Altova Logo On Wed, 4 Nov 2009 05:14:01 -0800, Mitch <Mitch@discussions.microsoft.com> wrote: >When I open Excel on one computer I get a SQUARE character where I have >carriage returns. On another computer these boxes are not visable. > >Can someone explain how I can make the squares with question marks hide on >my other PC. Hi this is an XSL (XML stylesheets) newsgroup. You actually want an XLS (Excel file format) newsgroup Look for newsgroups with 'Excel' in their title HTH Cheers - Neil ------------------------------------------------ Digital Media MVP : 2004-2009 http://mvp.support.microsoft.com/mvpfaqs]]> http://www.altova.com/list/microsoft.public.xsl/200911/msg1000306048.html When I open Excel on one computer I get a SQUARE character where I have carriage returns. On another computer these boxes are not visable. Can someone explain how I can make the squares with question marks hide on my other PC.]]> http://www.altova.com/list/microsoft.public.xsl/200911/msg1000306007.html Thanks a lot Martin. This is just what I needed. This will be of much help!! Cheers Ayan]]> http://www.altova.com/list/microsoft.public.xsl/200911/msg1000305983.html Ayan wrote: > <orders> > <OrdersTransaction> > <Item> > <!-- Changed Element:old --> > <Description>Marker</Description> > <!-- Changed Element:new --> > <Description>Mark er</Description> > </Item> > </OrdersTransaction> > <OrdersTransaction> > <Item> > <!-- Changed Element:old --> > <Description>Eraser</Description> > <!-- Changed Element:new --> > <Description>eraser</Description> > </Item> > <Item> > <!-- Added Element(s) --> > <comment>additional comments</comment> > </Item> > <Item> > <!-- Deleted Element(s) --> > <comment>Pen</comment> > </Item> > <Item> > <!-- Changed Element:old --> > <Description>Highlighter</Description> > <!-- Changed Element:new --> > <Description>highlighter</Description> > </Item> > </OrdersTransaction> > </orders> > > > "Deleted Element(s)" means, it was present in First XML, but not anymore in > Second XML. > "Added Element(s)" means, it was present in Second XML, but not in First XML. > "Changed Element:old" means it was like this in First XML but "Changed > Element:new" shows the changed > > version of it in Second XML. > > Now, these deleted, added or changed components can occur at any position in > the XML file. What I mean > > to say is, the tags can be deep inside. So there is no chance to know > beforehand. Only we can check the > > comments to know which part in the XML holds what. > > My question: > > I need to show HTML output in a simple table like this: > > ------------------------------------------------------------ > First XML | Second XML > ------------------------------------------------------------ > | > | Added Element(s): > | Item>comment > | value: additional comments > ------------------------------------------------------------ > | > Deleted Element(s): | > Item>comment | > value: Pen | > ------------------------------------------------------------ > Changed Element:old | Changed Element:new > Item>Description | Item>Description > value: Highlighter | value: highlighter > ------------------------------------------------------------ Here is a sample stylesheet that should give you an idea: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html lang="en"> <head> <title>Example</title> </head> <body> <table> <thead> <tr> <th>First XML</th> <th>Second XML</th> </tr> </thead> <tbody> <xsl:apply-templates/> </tbody> </table> </body> </html> </xsl:template> <xsl:template match="comment()[. = ' Changed Element:old ']"> <tr> <td> <xsl:text>Changed element:old</xsl:text> <br/> <xsl:text>Item></xsl:text> <xsl:value-of select="name(following-sibling::*[1])"/> <br/> <xsl:text>value: </xsl:text> <xsl:value-of select="following-sibling::*[1]"/> </td> <td> <xsl:text>Changed element:new</xsl:text> <br/> <xsl:text>Item></xsl:text> <xsl:value-of select="name(following-sibling::comment()[. = ' Changed Element:new '][1]/following-sibling::*[1])"/> <br/> <xsl:text>value: </xsl:text> <xsl:value-of select="following-sibling::comment()[. = ' Changed Element:new '][1]/following-sibling::*[1]"/> </td> </tr> </xsl:template> <xsl:template match="comment()[. = ' Deleted Element(s) ']"> <tr> <td> <xsl:text>Deleted element(s):</xsl:text> <br/> <xsl:text>Item></xsl:text> <xsl:value-of select="name(following-sibling::*[1])"/> <br/> <xsl:text>value: </xsl:text> <xsl:value-of select="following-sibling::*[1]"/> </td> <td></td> </tr> </xsl:template> <xsl:template match="comment()[. = ' Added Element(s) ']"> <tr> <td></td> <td> <xsl:text>Added element(s):</xsl:text> <br/> <xsl:text>Item></xsl:text> <xsl:value-of select="name(following-sibling::*[1])"/> <br/> <xsl:text>value: </xsl:text> <xsl:value-of select="following-sibling::*[1]"/> </td> </tr> </xsl:template> <xsl:template match="text()"/> </xsl:stylesheet> Its output, when run against the XML sample you posted, is as follows: <html lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Example</title> </head> <body> <table> <thead> <tr> <th>First XML</th> <th>Second XML</th> </tr> </thead> <tbody> <tr> <td>Changed element:old<br>Item&gt;Description<br>value: Marker </td> <td>Changed element:new<br>Item&gt;Description<br>value: Mark er </td> </tr> <tr> <td>Changed element:old<br>Item&gt;Description<br>value: Eraser </td> <td>Changed element:new<br>Item&gt;Description<br>value: eraser </td> </tr> <tr> <td></td> <td>Added element(s):<br>Item&gt;comment<br>value: additional comments </td> </tr> <tr> <td>Deleted element(s):<br>Item&gt;comment<br>value: Pen </td> <td></td> </tr> <tr> <td>Changed element:old<br>Item&gt;Description<br>value: Highlighter </td> <td>Changed element:new<br>Item&gt;Description<br>value: highlighter </td> </tr> </tbody> </table> </body> </html> -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305636.html Hi Friends Greetings! I have an XML file which contains difference between two xml like this: <?xml version="1.0" encoding="UTF-8" ?> <orders> <OrdersTransaction> <Item> <!-- Changed Element:old --> <Description>Marker</Description> <!-- Changed Element:new --> <Description>Mark er</Description> </Item> </OrdersTransaction> <OrdersTransaction> <Item> <!-- Changed Element:old --> <Description>Eraser</Description> <!-- Changed Element:new --> <Description>eraser</Description> </Item> <Item> <!-- Added Element(s) --> <comment>additional comments</comment> </Item> <Item> <!-- Deleted Element(s) --> <comment>Pen</comment> </Item> <Item> <!-- Changed Element:old --> <Description>Highlighter</Description> <!-- Changed Element:new --> <Description>highlighter</Description> </Item> </OrdersTransaction> </orders> "Deleted Element(s)" means, it was present in First XML, but not anymore in Second XML. "Added Element(s)" means, it was present in Second XML, but not in First XML. "Changed Element:old" means it was like this in First XML but "Changed Element:new" shows the changed version of it in Second XML. Now, these deleted, added or changed components can occur at any position in the XML file. What I mean to say is, the tags can be deep inside. So there is no chance to know beforehand. Only we can check the comments to know which part in the XML holds what. My question: I need to show HTML output in a simple table like this: ------------------------------------------------------------ First XML | Second XML ------------------------------------------------------------ | | Added Element(s): | Item>comment | value: additional comments ------------------------------------------------------------ | Deleted Element(s): | Item>comment | value: Pen | ------------------------------------------------------------ Changed Element:old | Changed Element:new Item>Description | Item>Description value: Highlighter | value: highlighter ------------------------------------------------------------ Now, the tags "Item", "comment" etc are not fixed. It depends on the XML we are comparing. So need to track on the basis of <!-- Added Element(s) -->, <!-- Deleted Element(s) -->, <!-- Changed Element:new --> etc. and need to render the table printing the values and attributes in the tags. Please ask me anything you like. Thanks a ton in advance Ayan]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305613.html jai wrote: > I have a dateTime format as an XML element (<PDFTIMESTAMP>2009-10-09 > 13:10:58.00000</PDFTIMESTAMP>). This dateTime format is not accepted > by XSLT 2.0 using Saxon 9. > > I came to know that 2009-10-09T13:10:58.00000 is proper format for > dateTime. > > I actually do a sort using PDFTIMESTAMP inside a for-each loop as > below: > > <xsl:for-each-group select="current-group()" group-by="RECEIPTTYPE"> > > <xsl:sort select="max(PDFTIMESTAMP/xs:dateTime(.)" > order="descending"/> > > In xs:dateTime(.), the issue is comming as format of current dateTime > is not correct. If the XML element's value cannot be corrected to > acceptable format, what can i do to convert the the improper dateTime > comming in xs:dateTime(.) to work? If only the 'T' is missing then you can certainly do e.g. <xsl:sort select="max(PDFTIMESTAMP/xs:dateTime(concat(substring(., 1, 10), 'T', substring(., 11))))"/> -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305193.html Sanket wrote: > I have to check a value of a variable in XSLT, if it is null then i > have to set it to default "$" otherwise same value. > so for that i have written the following XSLT Logic: > > <XSL:variable name="dummy" select= "ArrayOfBookMark/BookMark > [ShortName='Asp-7041-EndVar1]/Value"/> > <XSL:choose> > <XSL:when test="($dummy!='')"> > <XSL:variable name="dummy1" select="$dummy"/> > </when> > <XSL:otherwise> > <XSL:variable name="dummy1" select="'$'"/> > </XSL:variable> > <XSL:otherwise> > </XSL:choose> You might want <xsl:variable name="dummy" select="ArrayOfBookMark/BookMark[ShortName='Asp-7041-EndVar1]/Value"/> <xsl:variable name="dummy1" select="if ($dummy) then $dummy else '$'"/> That is XSLT 2.0 supported by Saxon, Altova, Gestalt. If you use XSLT 1.0 then it is more difficult: <xsl:variable name="dummy" select="ArrayOfBookMark/BookMark[ShortName='Asp-7041-EndVar1]/Value"/> <xsl:variable name="dummy1"> <xsl:choose> <xsl:when test="$dummy"> <xsl:value-of select="$dummy"/> </xsl:when> <xsl:otherwise>$</xsl:otherwise> </xsl:choose> </xsl:variable> -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305162.html Hello, I have a dateTime format as an XML element (<PDFTIMESTAMP>2009-10-09 13:10:58.00000</PDFTIMESTAMP>). This dateTime format is not accepted by XSLT 2.0 using Saxon 9. I came to know that 2009-10-09T13:10:58.00000 is proper format for dateTime. I actually do a sort using PDFTIMESTAMP inside a for-each loop as below: <xsl:for-each-group select="current-group()" group-by="RECEIPTTYPE"> <xsl:sort select="max(PDFTIMESTAMP/xs:dateTime(.)" order="descending"/> In xs:dateTime(.), the issue is comming as format of current dateTime is not correct. If the XML element's value cannot be corrected to acceptable format, what can i do to convert the the improper dateTime comming in xs:dateTime(.) to work? Any help is much appreciated. Thanks!! Jai]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305179.html I have to check a value of a variable in XSLT, if it is null then i have to set it to default "$" otherwise same value. so for that i have written the following XSLT Logic: <XSL:variable name="dummy" select= "ArrayOfBookMark/BookMark [ShortName='Asp-7041-EndVar1]/Value"/> <XSL:choose> <XSL:when test="($dummy!='')"> <XSL:variable name="dummy1" select="$dummy"/> </when> <XSL:otherwise> <XSL:variable name="dummy1" select="'$'"/> </XSL:variable> <XSL:otherwise> </XSL:choose> Here in "dummy" i am copying the value comming from follwing XML.it is retriving value correctly in to "dummy". Condition also checking but the value assignment code for new variable "dummy1" is not working. <ArrayOfBookMark> <BookMark> <ShortName>Asp-7041-EndVar1</ShortName> <Value>12345</Value> </BookMark> </ArrayOfBookMark> please help... Quick response will be appriciated. -Sanket Sanket.chougule@gmail.com]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305159.html Brian wrote: > Here is the simple XML Block where I want to transform the ListNode items > into a comma separated list that gets inserted into a table cell. > > <XMLBlk BlkAttr="A001"> > <NodeA>Standard</NodeA> > <ListNode> > <ListItem>Item 1</ListItem> > <ListItem>Item 2</ListItem> > <ListItem>Item 3</ListItem> > </ListNode> > <AnotherNode></AnotherNode> > </XMLBlk> > > The list output would be "Item 1, Item 2, Item 3" With XSLT 2.0 creating the comma separated list is as easy as <xsl:template match="ListNode"> <xsl:value-of select="ListItem" separator=", "/> </xsl:template> With XSLT 1.0 you need <xsl:template match="ListNode"> <xsl:for-each select="ListItem"> <xsl:value-of select="."/> <xsl:if test="position() != last()">, </xsl:if> </xsl:for-each> </xsl:template> > My table is somehow creates the CSL but inserts the individual items into > what appears to be sub-cells. I get word wrapping on the "Item 1" text > before it writes the "Item 2" text in the table cell. > > Question... what is the best way to structure this transform so that the > cell just gets a CSL and wraps the content if it exceeds the width of the > table cell? What kind of output do you create with the XSLT? Is that HTML? -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305106.html Yes... I'm outputting to HTML... I'll have to dig into the XSLT 2.0 standard and see how much I can simplify. I am using 1.0 because my list item logic is the same as your 1.0 example. Were you able to access the attachment? "Martin Honnen" wrote: > Brian wrote: > > > Here is the simple XML Block where I want to transform the ListNode items > > into a comma separated list that gets inserted into a table cell. > > > > <XMLBlk BlkAttr="A001"> > > <NodeA>Standard</NodeA> > > <ListNode> > > <ListItem>Item 1</ListItem> > > <ListItem>Item 2</ListItem> > > <ListItem>Item 3</ListItem> > > </ListNode> > > <AnotherNode></AnotherNode> > > </XMLBlk> > > > > The list output would be "Item 1, Item 2, Item 3" > > With XSLT 2.0 creating the comma separated list is as easy as > > <xsl:template match="ListNode"> > <xsl:value-of select="ListItem" separator=", "/> > </xsl:template> > > With XSLT 1.0 you need > > <xsl:template match="ListNode"> > <xsl:for-each select="ListItem"> > <xsl:value-of select="."/> > <xsl:if test="position() != last()">, </xsl:if> > </xsl:for-each> > </xsl:template> > > > My table is somehow creates the CSL but inserts the individual items into > > what appears to be sub-cells. I get word wrapping on the "Item 1" text > > before it writes the "Item 2" text in the table cell. > > > > Question... what is the best way to structure this transform so that the > > cell just gets a CSL and wraps the content if it exceeds the width of the > > table cell? > > What kind of output do you create with the XSLT? Is that HTML? > > > -- > > Martin Honnen --- MVP XML > http://msmvps.com/blogs/martin_honnen/ > . >]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305127.html Hello Will Word 2010 now be a .NET implementation? Thanks - Studi1]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305111.html I inherited an XSLT that I'm trying to modify... I'm a novice at this but have been able to pick my way through a lot of changes. But this one has me stumped. Here is the simple XML Block where I want to transform the ListNode items into a comma separated list that gets inserted into a table cell. <XMLBlk BlkAttr="A001"> <NodeA>Standard</NodeA> <ListNode> <ListItem>Item 1</ListItem> <ListItem>Item 2</ListItem> <ListItem>Item 3</ListItem> </ListNode> <AnotherNode></AnotherNode> </XMLBlk> The list output would be "Item 1, Item 2, Item 3" My table is somehow creates the CSL but inserts the individual items into what appears to be sub-cells. I get word wrapping on the "Item 1" text before it writes the "Item 2" text in the table cell. Question... what is the best way to structure this transform so that the cell just gets a CSL and wraps the content if it exceeds the width of the table cell?]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305072.html Artist wrote: > At the website: > http://www.xsltfunctions.com/ > there are many xsl functions I need to have working in PHP5 on Windows > XP. On this site I cannot find any place to download any PHP extension > to support the functions in its "http://www.functx.com" namespace. If > anyone knows anything about this function library and how to get it > installed please let me know. That is all XSLT/XPath 2.0 so you need an XSLT 2.0 processor like Saxon 9 or AltovaXML tools. PHP 5 uses libxslt I think so that does not work with those functions. I think someone tries to make Saxon or AltovaXML tools callable from PHP but I can't find anything on sourceforge with a quick search. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305010.html At the website: http://www.xsltfunctions.com/ there are many xsl functions I need to have working in PHP5 on Windows XP. On this site I cannot find any place to download any PHP extension to support the functions in its "http://www.functx.com" namespace. If anyone knows anything about this function library and how to get it installed please let me know. -- If you desire to respond directly remove the "sj." from the domain name part of my email address. It is a spam jammer.]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000305008.html On Thu, 15 Oct 2009 13:48:01 -0700, Kelev <bbss45@hotmail.com(donotspam> wrote: >when I type a word at the spreadsheet at microsoft works, I see it in english >and when i do ENTER, remain writen in english >when I type in Hebrew, I see when I tipe in Hebrew but when I do ENTER, it >is written in gibrish >I whent to the control panel, regional and language and changed to Hebrew, >and I still can not see written in hebrew >please what to do to fix this problem? This is an XSL newsgroup, which deals with issues about XSL (the XML formatting language). You meant to post in a newsgroup about spreadsheets, for the file format XLS (not XSL ;-) I'd look for newsgroups with Excel in their title Cheers - Neil ------------------------------------------------ Digital Media MVP : 2004-2009 http://mvp.support.microsoft.com/mvpfaqs]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304966.html when I type a word at the spreadsheet at microsoft works, I see it in english and when i do ENTER, remain writen in english when I type in Hebrew, I see when I tipe in Hebrew but when I do ENTER, it is written in gibrish I whent to the control panel, regional and language and changed to Hebrew, and I still can not see written in hebrew please what to do to fix this problem? -- תודה לעוזרים Kelev]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304944.html Studi1 wrote: > I want to display it in MS Word after tranformation. (In this case, 'to > display' means to open a Word session ...). Maybe someone in microsoft.public.office.xml understands what you want to achieve and can help. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304404.html Studi1 wrote: > I have a WordML document and want to display it transformed using an XSLT > document. > - Without XSLT one opens a Word document efficiently directly in MS > Explorer (by a double click). > - Wirth XSLT I as a WordML beginner cannot see yet the way how to adopt > this concept of a Word session > -- I want that the object (Word document) opens the tool session > automattically. > -- Presently I only know how to open the tool session with Word first, and > to include the Word XML document by a command of the type 'File / Open / ...' > afterwards. Do you want to transform the WordML document to HTML? In which application do you want to display the transformation result? -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304389.html Studi1 wrote: > I am a WordML beginner and have a fundamental problem: We open our Word > documents from Explorer (double click) and would like to do so when we want > to transform an WordML document with XSLT as well. > > How can we do that? I don't understand what you want to achieve. Do you have a WordML document and want to apply an XSLT transformation to that? Or do you want to create a WordML document as the result of an XSLT transformation? -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304379.html derekmw wrote: > <a> > <b> > <c type="period"> > <key> > <d name="date">2006-09-12 00:00:00.0</d> > </key> > ...(many other elements, many which have nested elements 6-7 levels > deep) > </c> > <c type="period"> > <key> > <d name="date">2006-09-15 00:00:00.0</d> > </key> > ...(many other elements, many which have nested elements 6-7 levels > deep) > </c> > </b> > </a> > > From what I read/understood, with xsl, you have to specify all the > fields you want to copy over to the new xml transformation? If so, > that's just not an option as there are so many other elements within > the 'c' elements I want to sort by. > > What I need to do is find a quick way to sort the 'c' elements by the > 'd' element value (date). Any suggestions/direction would be > appreciated! With XSLT 1.0 you can put xsl:sort elements as children of the xsl:for-each or xsl:apply-templates elements. What you do then is up to you thus if you want to sort and then make a deep copy that is certainly possible e.g. <xsl:template match="b"> <xsl:copy> <xsl:for-each select="c"> <xsl:sort select="key/d[@name = 'date']"/> <xsl:copy-of select="."/> </xsl:for-each> </xsl:copy> </xsl:template> So the above is a template for 'b' elements that makes a shallow copy of the 'b' element and then processes the 'c' children, sorted by the text value of the "key/d[@name = 'date']" grandchild element and then simply makes a deep copy. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304378.html I want to display it in MS Word after tranformation. (In this case, 'to display' means to open a Word session ...). "Martin Honnen" wrote: > Studi1 wrote: > > I have a WordML document and want to display it transformed using an XSLT > > document. > > - Without XSLT one opens a Word document efficiently directly in MS > > Explorer (by a double click). > > - Wirth XSLT I as a WordML beginner cannot see yet the way how to adopt > > this concept of a Word session > > -- I want that the object (Word document) opens the tool session > > automattically. > > -- Presently I only know how to open the tool session with Word first, and > > to include the Word XML document by a command of the type 'File / Open / ...' > > afterwards. > > Do you want to transform the WordML document to HTML? In which > application do you want to display the transformation result? > > -- > > Martin Honnen --- MVP XML > http://msmvps.com/blogs/martin_honnen/ >]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304390.html I have a WordML document and want to display it transformed using an XSLT document. - Without XSLT one opens a Word document efficiently directly in MS Explorer (by a double click). - Wirth XSLT I as a WordML beginner cannot see yet the way how to adopt this concept of a Word session -- I want that the object (Word document) opens the tool session automattically. -- Presently I only know how to open the tool session with Word first, and to include the Word XML document by a command of the type 'File / Open / ...' afterwards. "Martin Honnen" wrote: > Studi1 wrote: > > > I am a WordML beginner and have a fundamental problem: We open our Word > > documents from Explorer (double click) and would like to do so when we want > > to transform an WordML document with XSLT as well. > > > > How can we do that? > > I don't understand what you want to achieve. Do you have a WordML > document and want to apply an XSLT transformation to that? Or do you > want to create a WordML document as the result of an XSLT transformation? > > > -- > > Martin Honnen --- MVP XML > http://msmvps.com/blogs/martin_honnen/ >]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304380.html Hello I am a WordML beginner and have a fundamental problem: We open our Word documents from Explorer (double click) and would like to do so when we want to transform an WordML document with XSLT as well. How can we do that? Best regards - Studi1]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304371.html Hi all, I've been stuck on this issue for a while. I need to sort elements in an xml file but have been unable to. First of all, I'm new to xsl. But here is the general layout of my xml: <a> <b> <c type="period"> <key> <d name="date">2006-09-12 00:00:00.0</d> </key> ...(many other elements, many which have nested elements 6-7 levels deep) </c> <c type="period"> <key> <d name="date">2006-09-15 00:00:00.0</d> </key> ...(many other elements, many which have nested elements 6-7 levels deep) </c> </b> </a> From what I read/understood, with xsl, you have to specify all the fields you want to copy over to the new xml transformation? If so, that's just not an option as there are so many other elements within the 'c' elements I want to sort by. What I need to do is find a quick way to sort the 'c' elements by the 'd' element value (date). Any suggestions/direction would be appreciated! Thanks.]]> http://www.altova.com/list/microsoft.public.xsl/200910/msg1000304344.html XMLmind is happy to announce the version 4.5 of XMLmind XML Editor. _____________________________________________ XMLmind XML Editor Personal Edition 4.5 can be downloaded from http://www.xmlmind.com/xmleditor/download.shtml Professional Edition users, please upgrade using this form: http://www.xmlmind.com/store/download.php (The above form is usually accessed through http://www.xmlmind.com/xmleditor/upgrade.html.) _____________________________________________ v4.5 (September 24, 2009): DITA support is now bundled in XMLmind XML Editor. This support has been greatly enhanced. It is now as comprehensive as DocBook support in XMLmind XML Editor. Most of the enhancements come from XMLmind DITA Converter. XMLmind DITA Converter (ditac for short) allows to convert the most complex DITA 1.1 documents to production-quality XHTML 1.0, XHTML 1.1, HTML 4.1, Java[tm] Help, HTML Help, PDF, PostScript[r], RTF (can be opened in Word 2000+), WordprocessingML (can be opened in Word 2003+), Office Open XML (.docx, can be opened in Word 2007+), OpenOffice (.odt, can be opened in OpenOffice.org 2+). XMLmind DITA Converter is free, open source, software licensed under the very liberal terms of the Mozilla Public License version 1.1. More information in http://www.xmlmind.com/ditac/ _____________________________________________ More information in http://www.xmlmind.com/xmleditor/changes.html -- XMLmind XML Editor Information List xmleditor-announce@xmlmind.com http://www.xmlmind.com/mailman/listinfo/xmleditor-announce]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303588.html XMLmind is happy to announce the first release of XMLmind DITA Converter. XMLmind DITA Converter, which is open source software, can be freely downloaded from: http://www.xmlmind.com/ditac/download.shtml ________________________________________________ XMLmind DITA Converter v1.0 (September 23, 2009) XMLmind DITA Converter (ditac for short) allows to convert the most complex DITA 1.1 documents to production-quality XHTML 1.0, XHTML 1.1, HTML 4.1, Java[tm] Help, HTML Help, PDF, PostScript[r], RTF (can be opened in Word 2000+), WordprocessingML (can be opened in Word 2003+), Office Open XML (.docx, can be opened in Word 2007+), OpenOffice (.odt, can be opened in OpenOffice.org 2+). XMLmind DITA Converter has been developed in order to be integrated in the following XMLmind commercial products: * XMLmind XML Editor, * XMLmind XSL-FO Converter. As such, XMLmind DITA Converter is professionally developed software, well tested, well documented and well supported. XMLmind DITA Converter is free, open source, software licensed under the very liberal terms of the Mozilla Public License version 1.1. All this makes XMLmind DITA Converter a very serious alternative to using the DITA Open Toolkit. More information in http://www.xmlmind.com/ditac/. _______________________________________________ ditac-support mailing list ditac-support@xmlmind.com http://www.xmlmind.com/mailman/listinfo/ditac-support]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303513.html Barnum wrote: > Hmmm.... I've been thinking about the fact that I need to use the > predicate also in the preceding-sibling clause. > This must mean that my first select: <xsl:variable name="fie" > select="$in/foo[@name='1']" /> > gives a node set where the nodes still have the original sibling > information. > > So, a select only gives a selection from a node set, and the original > node set information is still there? I am not sure I understand what you are asking but XPath operates on a tree model and any node selection selects nodes in that tree where the tree remains intact meaning any parent/child/sibling/ancestor relationships continue to exist. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303392.html On 22 Sep, 13:09, Martin Honnen <mahotr...@yahoo.de> wrote: > Barnum wrote: > > Hmmm.... I've been thinking about the fact that I need to use the > > predicate also in the preceding-sibling clause. > > This must mean that my first select: <xsl:variable name=3D"fie" > > select=3D"$in/foo[@name=3D'1']" /> > > gives a node set where the nodes still have the original sibling > > information. > > > So, a select only gives a selection from a node set, and the original > > node set information is still there? > > I am not sure I understand what you are asking but XPath operates on a > tree model and any node selection selects nodes in that tree where the > tree remains intact meaning any parent/child/sibling/ancestor > relationships continue to exist. > > -- > > =A0 =A0 =A0 =A0 Martin Honnen --- MVP XML > =A0 =A0 =A0 =A0http://msmvps.com/blogs/martin_honnen/ That was exactly what I meant: "any parent/child/sibling/ancestor relationships continue to exist." Thanks!]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303393.html Hmmm.... I've been thinking about the fact that I need to use the predicate also in the preceding-sibling clause. This must mean that my first select: <xsl:variable name="fie" select="$in/foo[@name='1']" /> gives a node set where the nodes still have the original sibling information. So, a select only gives a selection from a node set, and the original node set information is still there? Thanks for any insight.]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303388.html Atila wrote: > How do I remove linefeeds with xslt transform? > I do not want to use normailze-space() as it modifies the text. I want to > count whitespaces as 1 characater as I have maxLength constraint. > substring(element,1,2000) counts more than 2000 as whitespaces count more > than 1 character I don't understand what you want to achieve. If you want to remove a certain character you can use the translate function e.g. translate(foo, '&#10;', '') will remove any linefeed character (where that code needs to be put in an XML document or other environment where '&#10;' denotes a linefeed character). -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303128.html How do I remove linefeeds with xslt transform? I do not want to use normailze-space() as it modifies the text. I want to count whitespaces as 1 characater as I have maxLength constraint. substring(element,1,2000) counts more than 2000 as whitespaces count more than 1 character]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303125.html Rudolf wrote: > height is an attribute in the xml > > i am using XSLT2.0 Here is an example, assuming an XML input alike <data> <item height="10"/> <item height="20"/> <item height="30"/> </data> then this stylesheet below <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:mf="http://example.com/2009/mf" xmlns="http://www.w3.org/2000/svg" exclude-result-prefixes="xs mf"> <xsl:output indent="yes"/> <xsl:template match="/"> <svg> <xsl:call-template name="mf:make-rects"> <xsl:with-param name="items" select="data/item"/> <xsl:with-param name="xcoord" select="10"/> <xsl:with-param name="ycoord" select="10"/> </xsl:call-template> </svg> </xsl:template> <xsl:template name="mf:make-rects"> <xsl:param name="items" as="element()*"/> <xsl:param name="xcoord" as="xs:integer"/> <xsl:param name="ycoord" as="xs:integer"/> <xsl:if test="$items[1]"> <rect x="{$xcoord}" y="{$ycoord}" width="10" height="{$items[1]/@height}" fill="green"/> <xsl:call-template name="mf:make-rects"> <xsl:with-param name="items" select="$items[position() gt 1]"/> <xsl:with-param name="xcoord" select="$xcoord"/> <xsl:with-param name="ycoord" select="$ycoord + 1 + xs:integer($items[1]/@height)"/> </xsl:call-template> </xsl:if> </xsl:template> </xsl:stylesheet> creates the following XML: <?xml version="1.0" encoding="UTF-8"?> <svg xmlns="http://www.w3.org/2000/svg"> <rect x="10" y="10" width="10" height="10" fill="green"/> <rect x="10" y="21" width="10" height="20" fill="green"/> <rect x="10" y="42" width="10" height="30" fill="green"/> </svg> -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303004.html Rudolf wrote: > I am trying to draw SVG using the information in an XML using XSL. So > basiccally for this purpose inside a for loop i need to keep track of > the coordinates. > > For instance something like this : > > <xsl:variable name="xcoord" select="10"/> > <xsl:variable name="ycoord" select="10"/> > <xsl:for-each ......> > <draw rectangle at xcoord and ycoord/> > <update value of xcoord and ycoord> > </xsl:for-each> > > so i need to figure out a way to update a values of xcoord and ycoord. > I cannot use the position() function for this since the update depends > on a third variable 'height' which is constantly changing .. so new > ycoord = ycoord + height. And where do you get the height from? Is that an element or attribute value in the XML input? Also do you use XSLT 1.0 or 2.0? With 1.0 you could write a named, recursive template with some parameters, with 2.0 you could write a function. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302978.html height is an attribute in the xml i am using XSLT2.0]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000303003.html I am trying to draw SVG using the information in an XML using XSL. So basiccally for this purpose inside a for loop i need to keep track of the coordinates. For instance something like this : <xsl:variable name="xcoord" select="10"/> <xsl:variable name="ycoord" select="10"/> <xsl:for-each ......> <draw rectangle at xcoord and ycoord/> <update value of xcoord and ycoord> </xsl:for-each> so i need to figure out a way to update a values of xcoord and ycoord. I cannot use the position() function for this since the update depends on a third variable 'height' which is constantly changing .. so new ycoord = ycoord + height. Thanks]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302952.html Rudolf wrote: > Hi, I am really new to XSL. I was wondering if it is possible in xsl > to reassign variables. No, it is not possible. XSLT is a declarative programming language, not a procedural one. If you show us an XML input sample you have and the corresponding output you want to create with XSLT then we can suggest an XSLT way of achieving that. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302889.html Hi, I am really new to XSL. I was wondering if it is possible in xsl to reassign variables. so for instance this piece of code does not work: <xsl:if test="$y &lt;2"> <xsl:variable name="x" select="5" /> </xsl:if> when i try and use x afterwards, it gives me the following error: "Error during XSLT transformation: An unknown error has occurred ()" The following code gives me an error as well: <xsl:variable name="height"/> <xsl:if test="$y &lt;2"> <xsl:variable name="x" select="5" /> </xsl:if> "Error during XSLT transformation: Variable binding shadows variable binding within the same template." I am not sure how to achieve what i am trying to do. any help is appreciated.]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302862.html Barnum wrote: > still struggling with XPath 1.0, now it's the replace function (only > in 2.0) I need. > Is there a work-around for that in 1.0? Not in XPath 1.0. In XSLT 1.0 you can write a recursive, named template that implements the string replacement: http://www.dpawson.co.uk/xsl/sect2/replace.html#d9701e43 -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302825.html On 14 Sep, 12:54, Martin Honnen <mahotr...@yahoo.de> wrote: > Barnum wrote: > > still struggling with XPath 1.0, now it's the replace function (only > > in 2.0) I need. > > Is there a work-around for that in 1.0? > > Not in XPath 1.0. In XSLT 1.0 you can write a recursive, named template > that implements the string replacement:http://www.dpawson.co.uk/xsl/sect2= /replace.html#d9701e43 > > -- > > =A0 =A0 =A0 =A0 Martin Honnen --- MVP XML > =A0 =A0 =A0 =A0http://msmvps.com/blogs/martin_honnen/ Works fine, thanks!]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302828.html Hi, still struggling with XPath 1.0, now it's the replace function (only in 2.0) I need. Is there a work-around for that in 1.0? Thanks!]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302822.html I think the if is right Martin, the more I think about it. Thanks for helping me see the trees =) "Martin Honnen" <mahotrash@yahoo.de> wrote in message news:ePd%233wsMKHA.504@TK2MSFTNGP06.phx.gbl... > Junkbox wrote: > >> The xml is basically >> <result status="ok"> >> <product> >> <nodes...> >> </product> >> <product> >> <nodes...> >> </product> >> <...> >> </result> >> >> I'm trying to lay out the product data in a 3x3 grid format with... >> >> <xsl:template match="result[@status='ok']"> >> <xsl:apply-templates/> >> </xsl:template> >> >> <xsl:template match="product"> >> <xsl:for-each select=".[position() mod 3 =1]"> > > That for-each does not make sense to me as the dot "." selects only a > single node. Maybe you simply want > <xsl:if test="position() mod 3 = 1"> > instead of the for-each. > > -- > > Martin Honnen --- MVP XML > http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302696.html Junkbox wrote: > The xml is basically > <result status="ok"> > <product> > <nodes...> > </product> > <product> > <nodes...> > </product> > <...> > </result> > > I'm trying to lay out the product data in a 3x3 grid format with... > > <xsl:template match="result[@status='ok']"> > <xsl:apply-templates/> > </xsl:template> > > <xsl:template match="product"> > <xsl:for-each select=".[position() mod 3 =1]"> That for-each does not make sense to me as the dot "." selects only a single node. Maybe you simply want <xsl:if test="position() mod 3 = 1"> instead of the for-each. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302649.html Barnum wrote: > is it correct that I cannot write my own XSLT functions in XSLT 1.0? Not in pure XSLT 1.0. Some XSLT processors support http://www.exslt.org/func/index.html. But moving to XSLT 2.0 with Saxon 9 (http://saxon.sourceforge.net/) or AltovaXML tools (http://www.altova.com/altovaxml.html) seems a better decision these days with XSLT 2.0 being a standard since 2007. > I am using Microsoft's XSLT processor, but it can't help much. (It > does support using VB scripts, but I don't want that....). Microsoft has three different XSLT 1.0 processors. There are the various MSXML versions (counting them as one processor version) which support writing extension functions in JScript or VBScript and there are two .NET XSLT processors, XslTransform and XslCompiledTransform, both of which support writing extension functions as .NET methods in .NET languages like C# or VB.NET. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302648.html On Fri, 11 Sep 2009 03:06:56 -0400, "Junkbox" <junkbox@foggyknockersrox.com> wrote: >Hi, > >I'm trying to get a for-each clause to work for laying out result sets and >I'm not really sure I understand why I can't get this to parse. > >The xml is basically ><result status="ok"> > <product> > <nodes...> > </product> > <product> > <nodes...> > </product> > <...> ></result> > >I'm trying to lay out the product data in a 3x3 grid format with... > ><xsl:template match="result[@status='ok']"> ><xsl:apply-templates/> ></xsl:template> > ><xsl:template match="product"> ><xsl:for-each select=".[position() mod 3 =1]"> ><...other stuff...> ></xsl:for-each> ></xsl:template> > >I can get this working other ways, but I'd like to know if someone can tell >me why the for-each statement is incorret? I'm not sure what you mean by "not working" but you need mod 3 = 0 to show rows split at multiples of 3 (0, 3, 6) and not 1 (1, 4, 7) HTH Cheers - Neil ------------------------------------------------ Digital Media MVP : 2004-2009 http://mvp.support.microsoft.com/mvpfaqs]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302641.html On 11 Sep, 12:36, Martin Honnen <mahotr...@yahoo.de> wrote: > Barnum wrote: > > is it correct that I cannot write my own XSLT functions in XSLT 1.0? > > Not in pure XSLT 1.0. Some XSLT processors supporthttp://www.exslt.org/fu= nc/index.html. > But moving to XSLT 2.0 with Saxon 9 (http://saxon.sourceforge.net/) or > AltovaXML tools (http://www.altova.com/altovaxml.html) seems a better > decision these days with XSLT 2.0 being a standard since 2007. > > > I am using Microsoft's XSLT processor, but it can't help much. (It > > does support using VB scripts, but I don't want that....). > > Microsoft has three different XSLT 1.0 processors. There are the various > MSXML versions (counting them as one processor version) which support > writing extension functions in JScript or VBScript and there are two > .NET XSLT processors, XslTransform and XslCompiledTransform, both of > which support writing extension functions as .NET methods in .NET > languages like C# or VB.NET. > > -- > > =A0 =A0 =A0 =A0 Martin Honnen --- MVP XML > =A0 =A0 =A0 =A0http://msmvps.com/blogs/martin_honnen/ Good point, I could use extension functions on .NET. Unfortunately, this must work on old "C++ platform" as well. Thanks!]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302650.html Hi, I'm trying to get a for-each clause to work for laying out result sets and I'm not really sure I understand why I can't get this to parse. The xml is basically <result status="ok"> <product> <nodes...> </product> <product> <nodes...> </product> <...> </result> I'm trying to lay out the product data in a 3x3 grid format with... <xsl:template match="result[@status='ok']"> <xsl:apply-templates/> </xsl:template> <xsl:template match="product"> <xsl:for-each select=".[position() mod 3 =1]"> <...other stuff...> </xsl:for-each> </xsl:template> I can get this working other ways, but I'd like to know if someone can tell me why the for-each statement is incorret? Thanks =)]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302634.html Hi, is it correct that I cannot write my own XSLT functions in XSLT 1.0? I am using Microsoft's XSLT processor, but it can't help much. (It does support using VB scripts, but I don't want that....). Thanks for any insight!]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302647.html Jack Maclean wrote: > <thread> > > <threadentry id="1760434" img="a.jpg" text="Start New Thread"> > > > <threadentry id="1760440" img="a.jpg" text="First Reply"> > </threadentry> > > <threadentry id="1760445" img="b.jpg" text="Second Reply"> > > <threadentry id="1760440" img="c.jpg" text="Reply to the reply."> > </threadentry> > > </treadentry> > > </threadentry> > > </thread> > the simplest XSL that I can get to work looks like this. Its not doing > what I want, it just outputs the root elements, no child elements. > > > <div xmlns:xsl="http://www.w3.org/TR/WD-xsl"> XSLT 1.0 has been standardized in 1999 and the namespace of XSLT is http://www.w3.org/1999/XSL/Transform. The namespace http://www.w3.org/TR/WD-xsl you are using is that of a predecessor of XSLT 1.0 that only old versions of MSXML (3.0 and earlier) support. Unless you have legacy code I would strongly suggest not to use that namespace anymore but use XSLT 1.0. As for your question, if you post the HTML output you want to generate for the XML input sample you have posted then we can help with an XSLT 1.0 stylesheet. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302587.html Hello, I'm kinda new to XSLT but not a beginner. I have a chunk of XML that holds recursive data. Here's a simple sample: <thread> <threadentry id="1760434" img="a.jpg" text="Start New Thread"> <threadentry id="1760440" img="a.jpg" text="First Reply"> </threadentry> <threadentry id="1760445" img="b.jpg" text="Second Reply"> <threadentry id="1760440" img="c.jpg" text="Reply to the reply."> </threadentry> </treadentry> </threadentry> </thread> I'm trying to use the documentElement.transform node method to convert this using XSLT into DHTML. I've been reading various articles on recursion in XLST but they all use templates and when I try to use templates per the samples IE complains. I just can't figure out how to do this. Totally stuck. Can anyone help? -------------------- the JavaScript snippet: gXSL = new ActiveXObject("Microsoft.XMLDOM"); gXSL.async="false"; gXSL.load("threads.xsl"); gThreadsXML = new ActiveXObject("Microsoft.XMLDOM"); gThreadsXML.async = "false"; gThreadsXML.loadXML(gThreadsXMLStr); if (gThreadsXML.parseError.errorCode != 0) return; f_ThreadContainer.innerHTML = gThreadsXML.documentElement.transformNode(gXSL.documentElement); ------------------------ the simplest XSL that I can get to work looks like this. Its not doing what I want, it just outputs the root elements, no child elements. <div xmlns:xsl="http://www.w3.org/TR/WD-xsl"> <TABLE BORDER="0" CELLSPACING="0" cellpadding="2"> <xsl:for-each select="threadentry"> <TR class="stateHeader"> <TD> <xsl:value-of select="@id"/> </TD> <TD> <xsl:value-of select="@img"/> </TD> <TD> <xsl:value-of select="@text"/> </TD> </TR> </xsl:for-each> </TABLE> </div>]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302574.html Frank Peterson wrote: > Just curious if there are any programs for doing XSL, that make it > easier to parse through XML files and see what you get, rather than > modifying a file in a text editor and hitting refresh in your browser. Just run the XSLT programatically, for instance from the command line (http://www.microsoft.com/downloads/details.aspx?FamilyID=2FB55371-C94E-4373-B0E9-DB4816552E41) BR, Julian]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302538.html Frank Peterson wrote: > Just curious if there are any programs for doing XSL, that make it > easier to parse through XML files and see what you get, rather than > modifying a file in a text editor and hitting refresh in your browser. Visual Studio 2005 and 2008 has support for running and debugging XSLT 1.0 stylesheet with .NET's XslCompiledTransform. And of course the "big" XML suites like Altova XML Spy, Stylus Studio or Oxygen allow you to run and debug stylesheets. -- Martin Honnen --- MVP XML http://msmvps.com/blogs/martin_honnen/]]> http://www.altova.com/list/microsoft.public.xsl/200909/msg1000302529.html