jai wrote:

> I have a dateTime format as an XML element (<PDFTIMESTAMP>2009-10-09
> 13:10:58.00000</PDFTIMESTAMP>). This dateTime format is not accepted
> by XSLT 2.0 using Saxon 9.
> 
> I came to know that 2009-10-09T13:10:58.00000 is proper format for
> dateTime.
> 
> I actually do a sort using PDFTIMESTAMP inside a for-each loop as
> below:
> 
> <xsl:for-each-group select="current-group()" group-by="RECEIPTTYPE">
> 
>                <xsl:sort select="max(PDFTIMESTAMP/xs:dateTime(.)"
> order="descending"/>
> 
> In xs:dateTime(.), the issue is comming as format of current dateTime
> is not correct. If the XML element's value cannot be corrected to
> acceptable format, what can i do to convert the the improper dateTime
> comming in xs:dateTime(.) to work?

If only the 'T' is missing then you can certainly do e.g.
         <xsl:sort 
select="max(PDFTIMESTAMP/xs:dateTime(concat(substring(., 1, 10), 'T', 
substring(., 11))))"/>

-- 

	Martin Honnen --- MVP XML
	http://msmvps.com/blogs/martin_honnen/