I also tried:

      <xsl:value-of select="ancestor::*[1]/@NUM"/>

But that gave me nothing.

"tshad" <toms@p...> wrote in message 
news:O3iPB7VFKHA.1376@T......
> Here is part of my xml:
>
>      <FORMPHOTOS>
>        <PHOTO NUM="1">
>          <FILENAME>09May001.jpg</FILENAME>
>          <FILETYPE>JPEG</FILETYPE>
>        </PHOTO>
>        <PHOTO NUM="2">
>          <FILENAME>09005.jpg</FILENAME>
>          <FILETYPE>JPEG</FILETYPE>
>        </PHOTO>
>        <PHOTO NUM="3">
>          <FILENAME>09002.jpg</FILENAME>
>          <FILETYPE>JPEG</FILETYPE>
>        </PHOTO>
>      </FORMPHOTOS>
>
> In my xsl sheet I am doing:
>
> <xsl:template match="FORMPHOTOS/PHOTO">
>  <xsl:choose>
>   <xsl:when test=". != ''">
>    <attachment>
>     <source>
>      <xsl:value-of select="../PHOTO/@NUM"/>
>     </source>
>    </attachment>
>   </xsl:when>
>  </xsl:choose>
> </xsl:template>
>
> In my source tag I am actually doing a little more but I am trying to get 
> the value of @NUM from the immediately preceding node.
>
> But this gets me '1' for all three PHOTOs.
>
> I want to get '1' for the first PHOTO, '2' for the 2nd PHOTO and '3' for 
> the 3rd PHOTO.
>
> It seems to always get the first one instead of the immediately preceding 
> one.
>
> Thanks,
>
> Tom
>