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Re: Replacing a string segment inside a variable?

From: ChrisG <chris@-----------.--->
To: NULL
Date: 7/21/2009 8:55:00 AM
Thanks Martin!  I did neglect to mention that I'm using xslt 1.0, so
I'm trying the latter part of your answer.

Cheers!


>
> XSLT 2.0:
> =A0 =A0<a href=3D"{replace(@ows_URL, '/DispForm',
> '/EditForm')}&amp;Source=3D{$PageUrl}">Click This</a>
> Note that replace takes a regular expression pattern as the second
> argument, I think I have choosen a string with '/DispForm' that does not
> contain any characters that need to be escaped but be careful if you
> want to change the above sample so that you escape anything that needs
> to be escaped.
>
> With XSLT 1.0 there is no replace unless you implement it with a named
> template that you then need to call inside of an xsl:attribute. On the
> other hand for the string you have doing
> =A0 =A0<a href=3D"{concat(substring-before(@ows_URL, '/'),
> '/EditForm.aspx')}&amp;Source=3D{$PageUrl}">Click This</a>
> should suffice.
>
> --
>
> =A0 =A0 =A0 =A0 Martin Honnen --- MVP XML
> =A0 =A0 =A0 =A0http://msmvps.com/blogs/martin_honnen/


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