Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: How to get node in the order the xml is given >Thread Next - Re: How to get node in the order the xml is given Re: How to get node in the order the xml is givenTo: NULL Date: 6/25/2009 11:55:00 PM Martin, Can you show me an example how to do this using xsl:for-each? Thanks a lot On Jun 25, 9:27=A0pm, Martin Honnen <mahotr...@yahoo.de> wrote: > Patrick.O .Ige wrote: > > I'm writing up a xsl against a xml file > > But the requirement is that they want me to display the nodes according= to > > the order the elements are being presented in the xml file. > > Any ideas how i can do this and is it possible? > > Simply process nodes with xsl:apply-templates or xsl:for-each, they will > =A0 be processed in document order, as long as you don't have an xsl:sort > inside. > > -- > > =A0 =A0 =A0 =A0 Martin Honnen --- MVP XML > =A0 =A0 =A0 =A0http://msmvps.com/blogs/martin_honnen/ | ||||||
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