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Re: Sort transformation result

From: "Markgoldin" <markgoldin_2000@-----.--->
To: NULL
Date: 5/18/2009 10:50:00 AM
Yes, you are right. Here it is:
<?xml version = "1.0" encoding="Windows-1252" standalone="yes"?>
<VFPData>
 <tree menuid="91" parentid="24" name="Adam Briel" link=" 
" salesrepid="670" category="4" exclude="true" comments="true"/>
 <tree menuid="83" parentid="24" name="Betty Mazon" link=" 
" salesrepid="325" category="4" exclude="true" comments="true"/>
 <tree menuid="93" parentid="24" name="Christina Martinez" link=" 
" salesrepid="625" category="4" exclude="true" comments="true"/>
 <tree menuid="48" parentid="20" name="Current Inventory" salesrepid="0" 
category="4" exclude="true" comments="true"/>
 <tree menuid="67" parentid="20" name="Customer Details" salesrepid="0" 
category="4" exclude="true" comments="true"/>
 <tree menuid="61" parentid="20" name="Customer Order Status" 
link="http://ufd-sql2008test/ReportServer?%2fCustomerPoStatus&amp;rs:Command=Render&amp;rc:Parameters=false&amp;rc:Zoom=100&amp;ccustno=&amp;SalesOrder=&amp;CustomerPO=&amp;Sku=&amp;OrderDate=&amp;ShipDateFrom=&amp;ShipDateTo= 
" salesrepid="0" category="4" exclude="true" comments="true"/>
 <tree menuid="24" parentid="20" name="Customer Reporting" salesrepid="0" 
category="4" exclude="true" comments="true"/>
 <tree menuid="20" parentid="1" name="Customer Service" salesrepid="0" 
category="4" exclude="true" comments="true"/>
 <tree menuid="62" parentid="20" name="Pick Plan Status" 
link="http://ufd-sql2008test/ReportServer?%2fPPStatus&amp;rs:Command=Render&amp;rc:Parameters=false&amp;rc:Zoom=100&amp;ccustno= 
" salesrepid="0" category="4" exclude="true" comments="true"/>
 <tree menuid="50" parentid="48" name="Price Lists" salesrepid="0" 
category="4" exclude="true" comments="true"/>
 <tree menuid="55" parentid="20" name="Product LookUp" 
link="http://ufd-sql2008test/ReportServer?%2fCustserviceOpenOrders&amp;rs:Command=Render&amp;rc:Parameters=false&amp;rc:Zoom=100&amp;ccustno= 
" salesrepid="0" category="4" exclude="true" comments="true"/>
 <tree menuid="47" parentid="48" name="Sku Attributes Reporting" 
link="http://ufd-sql2008test/ReportServer?%2fskuattributesFG&amp;rs:Command=Render&amp;rc:Parameters=false&amp;rc:Zoom=100&amp;ExcludeOnHand= 
" salesrepid="0" category="4" exclude="true" comments="true"/>
 <tree menuid="49" parentid="48" name="Sku Price List Preparation" 
salesrepid="0" category="4" exclude="true" comments="true"/>
 <tree menuid="95" parentid="24" name="Susan Finnane" link=" 
" salesrepid="375" category="4" exclude="true" comments="true"/>
 <tree menuid="1" name="United Feather and Down" salesrepid="0" category="0" 
exclude="true" comments="true"/>
 <tree menuid="90" parentid="24" name="Yoori Lee" link=" 
" salesrepid="650" category="4" exclude="true" comments="true"/>
</VFPData>

Sure, I could add an extra column "folder". But how would I know in advance 
which node is a parent?

"Martin Honnen" <mahotrash@y...> wrote in message 
news:OFVM3681JHA.4880@T......
> Markgoldin wrote:
>
>>     <xsl:apply-templates select="//tree[@parentid=$ID]">
>>     </xsl:apply-templates>
>>    </menu>
>> </xsl:template>
>> </xsl:stylesheet>
>>
>> I need to sort my tree showing folders first. Can someome help, please?
>
> Well you have not shown your XML at all. I guess it somehow contains 
> information that an item is a folder or something else so you need to sort 
> on that information. But without knowing your XML it is hard to make a 
> concrete suggestion.
> Sorting can be done inside the apply-templates e.g.
>   <xsl:apply-templates select="//tree[@parentid = $ID]">
>     <xsl:sort select="treetype"/>
>   </xsl:apply-templates>
>
>
> -- 
>
> Martin Honnen --- MVP XML
> http://msmvps.com/blogs/martin_honnen/ 




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