lister wrote:

> I am playing with XSLT to transform an XML file to HTML for rendering.
> I would like to pull in information from another lookup XML file but I
> can't find out how to address it in the stylesheet. XPath always seems
> to refer to the current file.

In XSLT 1.0 you can use the 'document' function which is powerful but as 
its easiest is used as e.g.
   document('file.xml')
See http://www.w3.org/TR/xslt#document

With XSLT and XPath 2.0 there is also the 'doc' function, see 
http://www.w3.org/TR/xpath-functions/#func-doc


Note also that XSLT allows you to pack data into the stylesheet e.g.

<xsl:stylesheet
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="1.0"
   xmlns:data="http://example.com/2009/mydata"
   exclude-result-prefixes="data">

<data:data>
   <lookup>
     <map key="01" value="January"/>
     <map key="02" value="February"/>
     ...
   </lookup>
</data:data>

<xsl:variable name="map" select="document('')/*/data:data/loopup/map"/>

</xsl:stylesheet>

but separating it into a second document is of course possible.


-- 

	Martin Honnen --- MVP XML
	http://msmvps.com/blogs/martin_honnen/