"Martin Honnen" <mahotrash@y...> a écrit dans le message de 
news:Od%23fsBZ0JHA.5744@T......
> Nicopil@mi wrote:
>> Hi everybody, i would like to sort alphabetically  the "rep" items by 
>> their id parameter.
>> Could you help me to make the xsl file please ?
>>
>> <repertoires>
>>   <rep id=nomdurep1>
>>     <param .... />
>>     <param .... />
>>   </rep>
>>   <rep id=nomdurep2>
>>     <param .... />
>>     <param .... />
>>   </rep>
>>   <rep id=nomdurep3>
>>        <rep id=nomdusousrep1>
>>          <param .... />
>>          <param .... />
>>       </rep>
>>        <rep id=nomdusousrep2>
>>          <param .... />
>>          <param .... />
>>       </rep>
>>      <param .... />
>>      <param .... />
>>   </rep>
>> </repertoires>
>
> Consider to post well-formed snippets of XML, otherwise we can't test our 
> solutions against your sample data.
> So here is some untested suggestion:
>
>   <xsl:template match="reportoires">
>     <xsl:copy>
>       <xsl:apply-templates select="rep">
>         <xsl:sort select="@id"/>
>       </xsl:apply-templates/>
>     </xsl:copy>
>   </xsl:template>
>
>   <xsl:template match="rep">
>     <xsl:copy>
>       <xsl:copy-of select="@*"/>
>       <xsl:apply-templates select="rep">
>         <xsl:sort select="@id"/>
>       </xsl:apply-templates/>
>       <xsl:copy-of select="param"/>
>     </xsl:copy>
>   </xsl:template>
>
> That solution assumes you want to sort the 'rep' children of the 
> 'repertoires' element by their 'id' attribute value and then assumes that 
> you want sort the 'rep' children of each 'rep' element again by their 'id' 
> attribute value.
>
> You haven't really explained what you want to to with the nested 'rep' 
> elements so the above is just an assumption of what you might want.
>
> -- 
>
> Martin Honnen --- MVP XML
> http://msmvps.com/blogs/martin_honnen/



exactly what i needed !!!
thank you very very very much
bye
Nico