Thanks once again Martin.That Worked well.Only thing i had to do was continue 
to use the following stmt.
buffer.Replace(@"xmlns=""http://schemas.datacontract.org/2004/07/EDIM.DataContracts""", "");

since without that, for some reason gave me a blank html output.



"Martin Honnen" wrote:

> Zest4Quest wrote:
> 
> >   I have the following function in C# which transforms the XML.
> > The GenerateXML() returns a string that represents the xml...
> > 
> >  public class XmlGenerator<T> where T : class
> >     {
> >         private T _dataContract;
> >         public XmlGenerator(T dataContract)
> >         {
> >             _dataContract = dataContract;
> >         }
> > 
> >         /// <summary>
> >         /// Generates the XML from the Object
> >         /// </summary>
> >         /// <returns></returns>
> >         private string GenerateXml()
> >         {
> >             UnicodeEncoding uniEncoding = new UnicodeEncoding();
> >             string buffer;
> > 
> >             DataContractSerializer ser = new 
> > DataContractSerializer(typeof(T));
> > 
> >             StreamWriter stWriter = null;
> >             MemoryStream memoryStream = new MemoryStream();
> >             XmlTextWriter xmlWriter = new XmlTextWriter(memoryStream, 
> > Encoding.Unicode);
> > 
> >             stWriter = new StreamWriter(memoryStream);
> >             ser.WriteObject(memoryStream, this._dataContract);
> > 
> >             buffer = Encoding.ASCII.GetString(memoryStream.GetBuffer());
> > 
> >             return 
> > buffer.Replace(@"xmlns=""http://schemas.datacontract.org/2004/07/EDIM.DataContracts""", "");
> >         }
> > 
> >         public string TransformXmlFinal(string xSLTFileName)
> >         {
> >              
> >             XmlDataDocument d = new XmlDataDocument();
> >             string sXML = this.GenerateXml();
> >             d.LoadXml(this.GenerateXml());
> > 
> >             XslCompiledTransform xslTransform = new XslCompiledTransform();
> > 
> >             xslTransform.Load(xSLTFileName);
> > 
> >             MemoryStream memoryStreamOutPut = new MemoryStream();
> >             xslTransform.Transform(d, null, memoryStreamOutPut);
> >             return Encoding.ASCII.GetString(memoryStreamOutPut.GetBuffer());
> 
> Don't use all those MemoryStreams, if you want a string then you can use 
> a StringWriter, there is no need to mess with MemoryStreams, Encodings, 
> byte arrays:
> 
> 
> 
>          private string GenerateXml()
>          {
>              string generatedXml;
> 
>              DataContractSerializer ser = new
> DataContractSerializer(typeof(T));
> 
>              using (StringWriter sw = new StringWriter())
>              {
>                  using (XmlWriter xw = XmlWriter.Create(sw))
>                  {
>                      ser.WriteObject(xw, this._dataContract);
>                      xw.Close();
>                  }
>                  generatedXml = sw.ToString();
>              }
>              return generatedXml;
> 
>          }
> 
>          public string TransformXmlFinal(string xSLTFileName)
>          {
> 
>              string sXML = this.GenerateXml();
> 
>              XslCompiledTransform xslTransform = new XslCompiledTransform();
> 
>              xslTransform.Load(xSLTFileName);
> 
>              StringWriter result = new StringWriter();
> 
>              xslTransform.Transform(new XPathDocument(new 
> StringReader(sXML)), null, result);
> 
>              return result.ToString();
> 
>          }
> 
> That way I hope the question marks should no longer appear as I suspect 
> they occured by using Encoding.ASCII to decode a byte array in a 
> different encoding and perhaps containing a byte order mark.
> 
> -- 
> 
> 	Martin Honnen --- MVP XML
> 	http://JavaScript.FAQTs.com/
>