I am using System.Xml.Xsl.XslCompiledTransform and the arugments are passed 
in as:

                                  xslArguments.AddParam("MessageTestList", 
string.Empty, MakeDocumentList(messageList));
                                  
xslArguments.AddParam("UnrecognizedSkuList", string.Empty, 
MakeDocumentList(unrecognizedChildSkus));
                                  
xslArguments.AddParam("DocumentTransactionId", string.Empty, 
documentTransactionId.ToString());
                                  
xslArguments.AddParam("CatalogConnectionString", string.Empty, 
catalogConnectionString);
                                  xslArguments.AddParam("IdenticalList", 
string.Empty, MakeDocumentList(connectionString, 
identicalDocumentTransactionIdDictionary));
                                  xslArguments.AddParam("NotProvidedList", 
string.Empty, MakeDocumentList(connectionString, 
notprovidedDocumentTransactionIdDictionary));

Where xslArguments is XsltArgumentList. And the function MakeDocumentList 
returns the XML string.

Thank you.

Kevin 


"Martin Honnen" wrote:

> Kevin Burton wrote:
> > I am using the XSLT processor that .NET uses. 
> 
> ..NET has two XSLT processors, System.Xml.Xsl.XslTransform and 
> System.Xml.Xsl.XslCompiledTransform.
> 
> > I am assuming that it is with 
> > the latest version of MSXML. 
> 
> MSXML is not part of the .NET framework.
> 
> > When I form the XML string and pass it as an 
> > argument it seems that the XSLT processor (at least with .NET) 
> > "automatically" turns it into an XmlDocument. 
> 
> Sorry, but that is certainly not the case. If you pass in a .NET string 
> with the AddParam method then the stylesheet sees it as an XPath string.
> Or how exactly do you use your XSLT processor and pass in arguments? If 
> you are really using .NET then you do that by calling the AddParam 
> method of an XsltArgumentList and passing that XsltArgumentList to the 
> Transform method.
> 
> I am not sure what you are doing exactly, passing in a string for param 
> foo and then doing $foo/someXpath should give a runtime error.
> 
> I think you need to provide details of the code you use, currently it is 
> not clear to me exactly what you are doing.
> 
> 
> -- 
> 
> 	Martin Honnen --- MVP XML
> 	http://JavaScript.FAQTs.com/
>