"Martin Honnen" <mahotrash@y...> wrote in message 
news:uAJXL61tIHA.6096@T......
> LJB wrote:
>
>> Does MSXML4.0 support exsl:node-set()? I found str:replace on the web but 
>> it requires the exsl:node-set() function. If I get that working how do I 
>> enter hex characters 0d0a in the search parameter?
>
> MSXML supports a node-set extension function, but not in the EXSL 
> namespace, rather in a Microsoft namespace urn:schemas-microsoft-com:xslt 
> so you would use e.g.
>   <xsl:stylesheet
>     xmlns:ms="urn:schemas-microsoft-com:xslt"
>     xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>     version="1.0"
>     exclude-result-prefixes="ms">
> then use
>     ms:node-set($var)
> instead of
>     exsl:node-set($var)
> As for those characters, with XML (and XSLT is XML) you can use numeric 
> character references e.g.
>   <xsl:param name="p1" select="'&#xD;&#xA;'"/>
>
>
> -- 
>
> Martin Honnen --- MVP XML
> http://JavaScript.FAQTs.com/

Thanks for the additional info however I need more help. I got the 
str:replace template from 
http://www.exslt.org/str/functions/replace/str.replace.template.xsl.html

Here are snippets of what I have but doesn't quite work.

<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:ms="urn:schemas-microsoft-com:xslt"
  xmlns:str="http://exslt.org/strings"
  exclude-result-prefixes="ms">
...........
<xsl:value-of select="str:replace(//DRAWING,'&#xD;&#xA;','&lt;br/&gt;')" />
...........
<xsl:template name="str:replace">
   <xsl:param name="string"
              select="''" />
   <xsl:param name="search"
              select="/.." />
   <xsl:param name="replace"
              select="/.." />
...........
all occurances of exsl:node-set have been replaced with ms:node-set as in:
            <xsl:for-each select="ms:node-set($search-nodes-rtf)/node()">

thanks
LJB