allen davidson wrote:

> 2.	Remove the namespaces xmlns="http://webservices.ecircle-ag.com/ecm" 
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> 
> My XML is:

Where is the XML?

> And my XSLT is:
> 
> <?xml version="1.0" encoding="utf-8"?>
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
> exclude-result-prefixes="#default xsl xsi">

exclude-result-prefixes relates to prefixes in the stylesheet, not those 
in the XML input.

> 
> 	<xsl:template match="/">
> 		<root>
> 		<xsl:copy-of select="."></xsl:copy-of>
> 		</root>
> 	</xsl:template>
> 	
> </xsl:stylesheet>
> 
> 
> The wrapping of <root></root> works but I cant strip out the namespaces (not 
> sure if i'm using the correct terminology here). Any Ideas (NB very new to 
> XML)

xsl:copy-of copies the complete node including any namespace nodes.
You need
   <xsl:template match="*">
     <xsl:element name="{local-name()}">
       <xsl:apply-templates select="@* | node()"/>
     </xsl:element>
   </xsl:template>
to strip namespaces from elements and, if you want to strip namespaces 
from attributes as well
   <xsl:template match="@*">
     <xsl:attribute name="{local-name()}">
       <xsl:value-of select="."/>
     </xsl:attribute>
   </xsl:template>
otherwise
   <xsl:template match="@*">
     <xsl:copy/>
   </xsl:template>


-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/