Thank you soooo much! I go it to work. But i have another question. What if 
i have a second level in the xml data? As in, //Animals/People? I tried:
select="//Animals/People[position() mod $columns = 0]">

But that didn't work. Any ideas?

Thank you again,

Julie.



"Martin Honnen" <mahotrash@y...> wrote in message 
news:%23UxXtlVnIHA.3780@T......
> Julie Smith wrote:
>> I'm trying to iterate through a collection and list them in a table going 
>> horizontally, not vertically.
>> Example of what i've currently got, but not working:
>>
>> <xsl:variable name="columns" select="5"/>
>> <table>
>> <xsl:for-each select="//People">
>>  <xsl:if test="(position() mod $columns) = 0"><tr></xsl:if>
>>   <td>
>>    <xsl:value-of select="@name"/>
>>   </td>
>>  <xsl:if test="(position() mod $columns) = 0"></tr></xsl:if>
>> </xsl:for-each>
>> </table>
>
>
> You need to use a different approach, like this:
>  <table>
>   <xsl:for-each select="//People[position() mod $columns = 0]">
>     <tr>
>       <xsl:for-each select=". | following-sibling::People[position() &lt; 
> $colums]">
>         <td>
>           <xsl:value-of select="@name"/>
>         </td>
>       </xsl:for-each>
>     </tr>
>   </xsl:for-each>
>  </table>
>
> -- 
>
> Martin Honnen --- MVP XML
> http://JavaScript.FAQTs.com/