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Re: Help? - xsl if statement

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 4/13/2008 1:28:00 PM

Julie Smith wrote:
> I'm trying to iterate through a collection and list them in a table 
> going horizontally, not vertically.
> Example of what i've currently got, but not working:
> 
> <xsl:variable name="columns" select="5"/>
> <table>
> <xsl:for-each select="//People">
>  <xsl:if test="(position() mod $columns) = 0"><tr></xsl:if>
>   <td>
>    <xsl:value-of select="@name"/>
>   </td>
>  <xsl:if test="(position() mod $columns) = 0"></tr></xsl:if>
> </xsl:for-each>
> </table>


You need to use a different approach, like this:
  <table>
   <xsl:for-each select="//People[position() mod $columns = 0]">
     <tr>
       <xsl:for-each select=". | following-sibling::People[position() 
&lt; $colums]">
         <td>
           <xsl:value-of select="@name"/>
         </td>
       </xsl:for-each>
     </tr>
   </xsl:for-each>
  </table>

-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/


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