I'm trying to iterate through a collection and list them in a table going 
horizontally, not vertically.
Example of what i've currently got, but not working:

<xsl:variable name="columns" select="5"/>
<table>
 <xsl:for-each select="//People">
  <xsl:if test="(position() mod $columns) = 0"><tr></xsl:if>
   <td>
    <xsl:value-of select="@name"/>
   </td>
  <xsl:if test="(position() mod $columns) = 0"></tr></xsl:if>
 </xsl:for-each>
</table>

Does that make sense?


"Anthony Jones" <Ant@y...> wrote in message 
news:uJQEcsTnIHA.4372@T......
>
> "Julie Smith" <julie@h...> wrote in message
> news:%23DxAu7RnIHA.3940@T......
>> Hi,
>> I want to do this:
>> <xsl:if test="true"></tr></xsl:if>
>>
>> However, I keep getting an error about the </tr>. How can i do this?
>>
>
>
> Since XSL is XML it needs to be well formed.  You can't therefore end an
> element conditionally in the way above.  Can you provide more detail of 
> the
> problem you want to solve?
>
>
> -- 
> Anthony Jones - MVP ASP/ASP.NET
>
>