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![]() | ![]() | ![]() | Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: How do get the root node? >Thread Next - Re: How do get the root node? Re: How do get the root node?To: NULL Date: 3/9/2008 7:05:00 PM
"Martin Honnen" <mahotrash@y...> wrote in message
news:e526kmgfIHA.4196@T......
> tshad wrote:
>> I forgot to add the xlst file I am using:
>
>> <xsl:template match="/">
>> <root_node>
>> <dataset>
>> <xsl:apply-templates>
>> <xsl:sort select="form/@primary" order="descending"/>
>> </xsl:apply-templates>
>> </dataset>
>> </root_node>
>> </xsl:template>
>
> Change that template to
>
> <xsl:template match="/*">
> <xsl:copy>
> <xsl:apply-templates>
> <xsl:sort select="form/@primary" order="descending"/>
> </xsl:apply-templates>
> </xsl:copy>
> </xsl:template>
>
That would work fine.
How do I also handle the "xmlns:dt" and the "dt:dt" to get the bin.base64 in
the xslt file?
<image>
<binary xmlns:dt="urn:schemas-microsoft-com:datatypes"
dt:dt="bin.base64" format="jpeg">
</image>
Thanks,
Tom
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