I tried and it worked. Thanks for your help, Martin!

P_Prdn

"Martin Honnen" wrote:

> P_Prdn wrote:
> 
> > I use the following xslt, however it didn't give the result I expect:
> > 
> > <xsl:stylesheet version="1.0" 
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> >   <xsl:template match="/Columns/*">
> >     <xsl:copy>
> >       <xsl:apply-templates>
> >         <xsl:sort select="@Seq" order="descending" data-type="number"/>
> >       </xsl:apply-templates>
> >     </xsl:copy>
> >   </xsl:template>
> > </xsl:stylesheet>
> 
> You need to process the child elements of Columns in sorted order like this:
> 
> <xsl:stylesheet
>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>    version="1.0">
> 
>    <xsl:output method="xml" indent="yes"/>
> 
>    <xsl:strip-space elements="*"/>
> 
>    <xsl:template match="Columns">
>      <xsl:copy>
>        <xsl:apply-templates select="*">
>          <xsl:sort select="@Seq" data-type="number"/>
>        </xsl:apply-templates>
>      </xsl:copy>
>    </xsl:template>
> 
>    <xsl:template match="@* | node()">
>      <xsl:copy>
>        <xsl:apply-templates select="@* | node()"/>
>      </xsl:copy>
>    </xsl:template>
> 
> </xsl:stylesheet>
> 
> -- 
> 
> 	Martin Honnen --- MVP XML
> 	http://JavaScript.FAQTs.com/
>