P_Prdn wrote:

> I use the following xslt, however it didn't give the result I expect:
> 
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>   <xsl:template match="/Columns/*">
>     <xsl:copy>
>       <xsl:apply-templates>
>         <xsl:sort select="@Seq" order="descending" data-type="number"/>
>       </xsl:apply-templates>
>     </xsl:copy>
>   </xsl:template>
> </xsl:stylesheet>

You need to process the child elements of Columns in sorted order like this:

<xsl:stylesheet
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="1.0">

   <xsl:output method="xml" indent="yes"/>

   <xsl:strip-space elements="*"/>

   <xsl:template match="Columns">
     <xsl:copy>
       <xsl:apply-templates select="*">
         <xsl:sort select="@Seq" data-type="number"/>
       </xsl:apply-templates>
     </xsl:copy>
   </xsl:template>

   <xsl:template match="@* | node()">
     <xsl:copy>
       <xsl:apply-templates select="@* | node()"/>
     </xsl:copy>
   </xsl:template>

</xsl:stylesheet>

-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/