On 28 nov, 13:48, Martin Honnen <mahotr...@yahoo.de> wrote:
> David Carricajo wrote:
> > I had a xml which looked like:

Thanks Martin.

I put the xml by heart but i'm finding the hard way that xsl is a full-
fledged programmig language in its own. Your code works smoothly but i
failed to apply it to my code. My problem lies in sorting a xml tree
which looks like:

<root>
  <A>
     <B>
        <IDENT id="escatron"/>
        <POS>
          <C1 v="1">
          </C1>
          <C2 En="21.3">
          </C2>
        </POS>
        <POS>
          <C1 v="2">
          </C1>
          <C2 En="17.8">
          </C2>
        </POS>
     </B>
     <B>
        <IDENT id="supelec"/>
        <POS>
          <C1 v="1">
          </C1>
          <C2 En="1.1">
          </C2>
        </POS>
        <POS>
          <C1 v="3">
          </C1>
          <C2 En="3.5">
          </C2>
        </POS>
     </B>
   </A>
</root>

But i can't find the right sort based on the key par attributes
(C1::v, IDENT::id)  attributes , in other words, i'd like the tree
ordered so that it can be rendered like:

1;escatron;21.3;
1;supelec;1.1;
2;escatron;17.8;
3;supelec;3.5;

I think i should order when i'm in the A context since B context looks
too late for such task. But if try:

<xsl:template match="A">
  <xsl:apply templates>
     <xsl:sort select="number(/B/POS/C1/@v)" order="descending" data-
type="number"/>
  </xsl:apply templates>
</xsl:template match='A'>

the result in plain text looks rather like:

1;escatron;21.3;
2;escatron;17.8;
1;supelec;1.1;
3;supelec;3.5;

Any hint is appreciated.