"Joe Fawcett" <joefawcett@n...> schrieb im Newsbeitrag 
news:%23l9Au8xNIHA.4480@T......
> "Oliver Hirschi" <no-reply@F...> wrote in message 
> news:5rn72eF13hp3pU1@m......
>> Hi
>>
>> Can someone help me out as to how I can transform the following 
>> XML...
>> -----------
>> <Source>
>>    One <AAA>Two <BBB>Three <CCC>Four</CCC></BBB></AAA>
>> </Destination>
>> -----------
>> into this...
>> -----------
>> <Destination>
>>    One <DDD>Two <EEE>Three <FFF>Four</FFF>></EEE></DDD>
>> </Destination>
>> -----------
>>
>> - The elements could be any inteleaved...
>> - Is there a recursive function needed?
>> - How do I do that?
>>
>> Great thanks & regards,
>> -- 
>> Oliver Hirschi
>> http://www.FamilyHirschi.ch
>
> Assuming your original file is actually well-formed, ie. a Source 
> element as the root element then I would look at identity template, 
> but how do the mappings work, is AAA always turned into DDD etc?
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:template match="@*|node()">
> <xsl:copy>
> <xsl:apply-templates select="@*|node()"/>
> </xsl:copy>
> </xsl:template>
> <xsl:template match="Source">
> <Destination>
> <xsl:apply-templates select="@*|node()"/>
> </Destination>
> </xsl:template>
> <xsl:template match="AAA">
> <DDD>
> <xsl:apply-templates select="@*|node()"/>
> </DDD>
> </xsl:template>
> <!-- other override templates here -->
> </xsl:stylesheet>
>
> -- 
>
> Joe Fawcett (MVP - XML)
>
> http://joe.fawcett.name
>

Of course my original file is well-formed. It was a typing error...
It works - Thanks a lot - But I did not understand the functionality at 
all!
Could you explain me:

<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>

and all the calls:

<xsl:apply-templates select="@*|node()"/>

Thanks again & regards,
Oliver Hirschi