Sorry i forgot
Thanks for the reply the xml data looks like this:
It a very intersting xml since its produced by a webpart to show data from a 
sharepoint list.
I need the id in this tag <ListViewRow Id="4"> and i need to append it to a 
url  link.
Thanks in advance

<?xml version="1.0" encoding="utf-16"?>

<ListView xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
ViewID="47fe3de3-5911-4dd4-a82e-9ffd56c8d54b" 
ListID="8ba5b6b9-838f-4361-900e-ed15c1fdf478" DisplayName="Store 
Communications" SiteUrl="" AbsoluteUrl="" RootUrl="" DisplayFormUrl="" 
NewFormUrl="Lists/Store Communications/NewForm.aspx" 
EditFormUrl="Lists/Store Communications/EditForm.aspx" 
BaseType="GenericList" RowLimit="100" 
xmlns="FlexListViewer.ListViewerObjectModel">

<Fields>

<ListViewField Name="Attachments" DisplayName="Attachments" 
FieldType="Attachments" Hidden="false" LinkToItem="false" />

<ListViewField Name="LinkTitle" DisplayName="Title" FieldType="Computed" 
Hidden="false" LinkToItem="true" />

<ListViewField Name="Modified" DisplayName="Modified" FieldType="DateTime" 
Hidden="false" LinkToItem="false" />

<ListViewField Name="Author" DisplayName="Created By" FieldType="User" 
Hidden="false" LinkToItem="false" />

</Fields>

<Rows>

<ListViewRow Id="4">

<RowValues>

<ListViewRowValue FieldName="Attachments">

<Parts>

<ListViewRowValuePart>False</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

<ListViewRowValue FieldName="LinkTitle">

<Parts>

<ListViewRowValuePart>test1234</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

<ListViewRowValue FieldName="Modified">

<Parts>

<ListViewRowValuePart>10/5/2007</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

<ListViewRowValue FieldName="Author">

<Parts>

<ListViewRowValuePart></ListViewRowValuePart>

<ListViewRowValuePart>387</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

</RowValues>

</ListViewRow>

<ListViewRow Id="1">

<RowValues>

<ListViewRowValue FieldName="Attachments">

<Parts>

<ListViewRowValuePart>True</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

<ListViewRowValue FieldName="LinkTitle">

<Parts>

<ListViewRowValuePart>July Store Comms</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

<ListViewRowValue FieldName="Modified">

<Parts>

<ListViewRowValuePart>10/5/2007</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

<ListViewRowValue FieldName="Author">

<Parts>

<ListViewRowValuePart></ListViewRowValuePart>

<ListViewRowValuePart>1073741823</ListViewRowValuePart>

</Parts>

</ListViewRowValue>

</RowValues>

</ListViewRow>

</Rows>

</ListView>

"Joe Fawcett" <joefawcett@n...> wrote in message 
news:OE%23t2unBIHA.3900@T......
> "rote" <naijacoder@h...> wrote in message 
> news:Ohyiq0lBIHA.4496@T......
>>I have a variable like so but 'm using an apply templates
>>
>> <xsl:apply-templates select="lv:Rows/lv:ListViewRow/lv:RowValues">
>>
>> <xsl:with-param name="fields" select="lv:Fields"/>
>>
>> </xsl:apply-templates>
>>
>>
>> I would like to break out from the apply template and use the variable 
>> below
>> You will notice  that the apply templates above node ficnishes at 
>> lv:RowValues but i need /lv:ListView/lv:Rows/lv:ListViewRow
>>
>>
>> <xsl:variable name="listViewRowID" 
>> select="/lv:ListView/lv:Rows/lv:ListViewRow/@Id" />
>>
>> <a href="{$DispUrl}?ID={$listViewRowID}&amp;Source={$currentPage}">
>>
>> <xsl:value-of select="$fieldValueParts/lv:ListViewRowValuePart[position() 
>> = 1]/text()"/>
>>
>> </a>
>>
>> Any ideas
>>
>>
> Not sure what you mean by break out and don't have the full structure of 
> your XML to hand but you can use the parent axis to move up the tree, the 
> parent axis is normally shortened to two full stops (..).
> So if you are currently at lv:RowValues the parent is rached via .. and 
> the parent's Id attribute is ../@Id.
> As an aside 'lv:ListViewRowValuePart[position() = 1]' can be shortened to 
> 'lv:ListViewRowValuePart[1]', the 'position() =' is implicit for integer 
> predicates.
> -- 
>
> Joe Fawcett (MVP - XML)
> http://joe.fawcett.name
>
>