"rote" <naijacoder@h...> wrote in message 
news:Ohyiq0lBIHA.4496@T......
>I have a variable like so but 'm using an apply templates
>
> <xsl:apply-templates select="lv:Rows/lv:ListViewRow/lv:RowValues">
>
> <xsl:with-param name="fields" select="lv:Fields"/>
>
> </xsl:apply-templates>
>
>
> I would like to break out from the apply template and use the variable 
> below
> You will notice  that the apply templates above node ficnishes at 
> lv:RowValues but i need /lv:ListView/lv:Rows/lv:ListViewRow
>
>
> <xsl:variable name="listViewRowID" 
> select="/lv:ListView/lv:Rows/lv:ListViewRow/@Id" />
>
> <a href="{$DispUrl}?ID={$listViewRowID}&amp;Source={$currentPage}">
>
> <xsl:value-of select="$fieldValueParts/lv:ListViewRowValuePart[position() 
> = 1]/text()"/>
>
> </a>
>
> Any ideas
>
>
Not sure what you mean by break out and don't have the full structure of 
your XML to hand but you can use the parent axis to move up the tree, the 
parent axis is normally shortened to two full stops (..).
So if you are currently at lv:RowValues the parent is rached via .. and the 
parent's Id attribute is ../@Id.
As an aside 'lv:ListViewRowValuePart[position() = 1]' can be shortened to 
'lv:ListViewRowValuePart[1]', the 'position() =' is implicit for integer 
predicates.
-- 

Joe Fawcett (MVP - XML)
http://joe.fawcett.name