"TarTar" <spam.spam@l...> wrote in message 
news:%238uJJxPBIHA.4836@T......
> Hi Dimitre,
>
> Thanks a lot! Now the code works like a charm.
>
> BTW
> Could you explain (or point to a resource) what's the differenece between 
> //name[position() > 10] and (//name)[position() > 10] ? The former one 
> (with brackets) works perfectly - but why?
>
> Leszek
>
The first retrieves name elements when they have a position() greater than 
ten within their siblings.
The second one retrieves all the name elements as one node-set and then 
filters them, removing the first ten.
An example:

<data>
<names>
<name att="1" block="1"/>
<name att="2" block="1"/>
<name att="3" block="1"/>
<name att="4" block="1"/>
<name att="5" block="1"/>
</names>
<names>
<name att="1" block="2"/>
<name att="2" block="2"/>
<name att="3" block="2"/>
<name att="4" block="2"/>
<name att="5" block="2"/>
</names>
<names>
<name att="1" block="3"/>
<name att="2" block="3"/>
<name att="3" block="3"/>
<name att="4" block="3"/>
<name att="5" block="3"/>
</names>
</data>

//name[position() > 3] gives:
<name att="4" block="1"/>
<name att="5" block="1"/>
<name att="4" block="2"/>
<name att="5" block="2"/>
<name att="4" block="3"/>
<name att="5" block="3"/>

(//name)[position() > 3] gives:
<name att="4" block="1"/>
<name att="5" block="1"/>
<name att="1" block="2"/>
<name att="2" block="2"/>
<name att="3" block="2"/>
<name att="4" block="2"/>
<name att="5" block="2"/>
<name att="1" block="3"/>
<name att="2" block="3"/>
<name att="3" block="3"/>
<name att="4" block="3"/>
<name att="5" block="3"/>

so if all the names are siblings anyway the two expressions give the same 
result.

-- 

Joe Fawcett (MVP - XML)

http://joe.fawcett.name