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![]() | ![]() | ![]() | Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries [Thread Prev] >Thread Next - Re: sorted distinct nodes with xsl sorted distinct nodes with xslTo: NULL Date: 9/6/2007 10:39:00 AM XML is like this. <R> <I U="6" S="Six"/> <I U="1" S="One"/> <I U="2" S="Two"/> <I U="1" S="One"/> <I U="2" S="Two"/> <I U="1" S="One"/> </R> What to get all 'I' nodes with unique 'U' and sorted by 'U' otherwise want to print only. One Two Six in xsl. thanks, Praveen | ![]() | ![]() | ![]() |
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