"ML" wrote:

> Are you referring to XPath wildcards?
> 
> E.g.:
> "//cell" will give you all cell nodes anywhere in the XML.
> 
> Is this what you need? For a more accurate answer post an example of the 
> output XML.
> 
> 
> ML
> 
> ---
> http://milambda.blogspot.com/


Thanks ML, you r trying to help me out but i think i did not explain very 
well what is my problem, here i am pasting my xml code and output that what i 
want; 

Although i have a big file but i just minimize and took only two child node, 
if you see my code so you can easily distingush by title name, My problem is 
i have two title info (data) and has same child nodes like "table, row, cell, 
db, idebtifier" but i want to display in different "table block" not display 
all db or identifier at one place. 

<Record>
	<content>	
				<!-- Title= Redundant Groups  -->			
			<field>
				<title>Redundant Group</title>
					<summary>3 identical protein(s) found.</summary>
					<content>
						<table>
							<row>
								<cell>
									<idebtifier>Q9D6L8</idebtifier>
								</cell>
								<cell>
									<db>dbj</db>
								</cell>
							</row>
						</table>
					</content>
			</field>
				<!--  Title= Database Cross-references  -->
			<field>
				<title>Database Cross-references</title>
					<summary>3 cross-reference(s) found </summary>
					<content>
						<table>
							<row>
								<cell>
									<db>GENE</db>
								</cell>
								<cell>
									<idebtifier>Z98T23</idebtifier>
								</cell>
							</row>
						</table>
					</content>
			</field>
	</content>
</Record>
 
 output:
 Title: Redundant Group
		 Identifier = Q9D6L8
		 db = dbj
Title: Database Cross-references
		Identifier = Z98T23
		db = GENE