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Transformation

From: Kniffel <kern@-------------.-->
To: NULL
Date: 5/14/2007 5:28:00 AM


Hi

i have questions around the XSLT-Tranformation.

my XML-file looks like this (first Examle):
<?xml version=3D"1.0" encoding=3D"utf-8"?>
<?xml-stylesheet type=3D"text/xsl" href=3D"dlt.xsl" ?>
<DLT>
  <Standardsprache  Sprache=3D"Deutsch"  Datei=3D"lang_german.xml" />
</DLT>

I don=B4t know how to get the values of "Sprache" or "Datei"?

+++++++++++++++++++++++++++++++++++++++++++

If it would look like this:
<?xml version=3D"1.0" encoding=3D"utf-8"?>
<?xml-stylesheet type=3D"text/xsl" href=3D"dlt.xsl" ?>
<DLT>
  <Standardsprache>
    <Sprache>Deutsch</Sprache>
    <Datei>lang_german.xml</Datei>
 </Standardsprache>
</DLT>

I am able to transform it with this:
<?xml version=3D'1.0'?>
<xsl:stylesheet version=3D"1.0" xmlns:xsl=3D"http://www.w3.org/1999/XSL/
Transform">
<xsl:output method=3D"html"/>
<xsl:template match=3D"/">
  <html><head></head><body>
    <xsl:apply-templates />
 </body></html>
</xsl:template>

  <xsl:template match=3D"Standardsprache">
    <xsl:for-each select=3D"*">
      <li>
        <xsl:value-of select=3D"." />
      </li>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

++++++++++++++++++++++++++++++++++++++++++++++

Now I get the two values in a list, but how can I get the values in
the first example?

Somebody have some references for me?

Greetings
Kniffel

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