You need to write a template that matches gig elements, and inside put some 
HTML:
<xsl:template match="gig">
  <p><xsl:value-of select="."/></p>
</xsl:template>


-- 

Joe Fawcett (MVP - XML)
http://joe.fawcett.name

"TheDude5B" <timbjames@g...> wrote in message 
news:1178796957.208072.60270@l......
> Hi,
>
> I have an xml document which to me is not formed very well, so is now
> causing me problems.
>
> The XML document looks like this:
>
> <club>
>  <Glasgow>
>     <venue>some venue</venue>
>     <address>some address</address>
>     <url>some url</url>
>     <gig>date name of band</gig>
>     <gig>date name of band</gig>
>  </Glasgow>
>  <London>
>     <venue>some venue</venue>
>     <address>some address</address>
>     <url>some url</url>
>     <gig>date name of band</gig>
>     <gig>date name of band</gig>
>     <gig>date name of band</gig>
>     <gig>date name of band</gig>
>  </London>
>  <Aberdeen>
>     <venue>some venue</venue>
>     <address>some address</address>
>     <url>some url</url>
>     <gig>date name of band</gig>
>     <gig>date name of band</gig>
>     <gig>date name of band</gig>
>  </Aberdeen>
> </club>
>
>
> as you can see the <club> node has <CITY> nodes and then a venue,
> address, url and then gig nodes. there can be multiple numbers of gig
> nodes and the number can be different for every city.
>
> I am not too sure how I will be able to display this in XSL? I have
> tried a few ways but the gigs always end up on the same line instead
> of being separate form each other.
>
> the code I currently have is:
>
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/
> Transform">
> <xsl:output method="html"/>
> <xsl:preserve-space elements="gig"/>
> <xsl:template match="/">
> <xsl:for-each select="/clubnme/*">
> <h3><xsl:apply-templates select="./venue" /></h3>
> <h4><xsl:apply-templates select="./address" /></h4>
> <p><font class="gigdate"><xsl:apply-templates select="./gig" /></font>
> </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>
>
> hope someone can help.
>