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Re: XSL question

From: "Dimitre Novatchev" <dimitren@---.---.-->
To: NULL
Date: 4/10/2007 5:56:00 PM



"Bryan" <bcc@n...> wrote in message 
news:RxVSh.7090$Kd3.6527@n......
> Is there something wrong with this:
>
> <xsl:variable name="newline">
> <xsl:text>\n</xsl:text>
> </xsl:variable>
>
> I am trying to use perls XML::XSLT to process this xsl file, and it chokes 
> here.


There is nothing wrong with this code, but it is not probably what you want.

Try:

  <xsl:variable name="vNL" select="'&#xA;'"/>

The following transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>

 <xsl:template match="/">
  <xsl:variable name="newline">
     <xsl:text>\n</xsl:text>
  </xsl:variable>

  <xsl:variable name="vNL" select="'&#xA;'"/>

    <xsl:value-of  select="$newline"/>
    <xsl:value-of  select="$vNL"/>
    <xsl:value-of  select="$newline"/>
 </xsl:template>
</xsl:stylesheet>

when run on any source xml document (not used), produces this result:

\n
\n

Hope this helped.


Cheers,
Dimitre Novatchev

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