I think the solution is to use the decimal point in your XML and in an XSLT 
you can use xsl:decimal-format element and the format-number function.

-- 

Joe Fawcett (MVP - XML)

http://joe.fawcett.name

"Mike May" <mikemay@b...> wrote in message 
news:clyQh.30985$_Q.4600@f......
>I am attempting some XSLT processing on a machine with German regional 
>settings.  The attached test case illustrates the problem.  German has 
>commas as decimal separators.  Excel and other applications respect comma 
>as the decimal separator.
>
> xml data-------------
> <?xml version="1.0" encoding="utf-8" ?>
>     <data>
>      <item>103,3</item>
>      <item>104,4</item>
> </data>
>
> xsl script---------------
> <?xml version="1.0" encoding="utf-8" ?>
>    <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>  <xsl:output encoding="utf-8" />
>      <xsl:template match="/">
>      <xsl:value-of select="sum(data/item)" />
>  </xsl:template>
> </xsl:stylesheet>
>
> msxsl outputs NaN for the above.
>
> It behaves correctly outputting 207.7 when I change the decimal separators 
> to '.'.
>
> Do I need to stipulate the decimal separator?
>
> Please help if you can?
>
> Regards
> Mike May
>