RedLars wrote:

> Could you possibly show me a code example (or pseudo code) of how
> you'd solve this problem.

Assuming your are using MSXML or .NET as your XSLT processor you have an 
extension function msxsl:node-set that converts a result tree fragment 
into a node set so that you can apply XPath on it (without needing to 
chain transformations).

So you would do e.g.

<xsl:variable name="rtf">
<xsl:for-each select="computer">
	<xsl:sort select="@number" data-type="number"/>
         <xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>

then apply the node-set function e.g.

<xs:variable name="sorted-computers" select="msxsl:node-set($rtf)"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt">

then do the rest e.g.

<xsl:for-each select="$sorted-computers/computer">
	<a href="#{generate-id()}"><xsl:value-of select="@type"/><xsl:number
value="@number" format="001"/></a>
	<xsl:value-of select="concat(' floor: ', floor(@number div 10))"/>
	<xsl:value-of select="concat(' floor_sib: ', floor(following-
sibling::node()[1]/@number div 10))"/>
	<xsl:value-of select="concat(' floor_num: ', (following-
sibling::node()[1]/@number))"/>
	<xsl:if test="floor(@number div 10) != floor(following-sibling::node()
[1]/@number div 10)">
	           <br/>
          	</xsl:if>


-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/