shurik wrote:
> Here is an example, there is a text node within a variable A. The textnode 
> has disable-output-escaping="yes". I need to ouput the variable A into the 
> result tree preserving the disable-ouput-escaping setting. 
> 
> This template:
> 
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> xmlns:msxsl="urn:schemas-microsoft-com:xslt" >
> 	<xsl:template match="/">
> 		<xsl:variable name="A">
> 			<xsl:text disable-output-escaping="yes">&nbsp;</xsl:text>
> 		</xsl:variable>
> 		<xsl:copy-of select="msxsl:node-set($A)"/>
> 	</xsl:template>
> </xsl:stylesheet>
> 
> produces "&nbsp;" but I need " "

Why don't you just use <xsl:text>0xA0;</xsl:text> ?

To your question - XSLT spec doesn't allow such tricks:

"It is an error for output escaping to be disabled for a text node that 
is used for something other than a text node in the result tree. Thus, 
it is an error to disable output escaping for an xsl:value-of or 
xsl:text element that is used to generate the string-value of a comment, 
processing instruction or attribute node; it is also an error to convert 
a result tree fragment to a number or a string if the result tree 
fragment contains a text node for which escaping was disabled. "

In short - disable-output-escaping is output serialization feature and 
definitely won't work inside transformation.

-- 
Oleg Tkachenko [XML MVP, MCPD]
http://blog.tkachenko.com | http://www.XmlLab.Net | http://www.XLinq.Net