On Feb 2, 1:36 pm, dvdas...@yahoo.com wrote:
> Greetings,
>
> I need to sort this XML by the value in the sequence attribute and I
> was hoping for a little help as the XSL i have created is not doing
> the job.
>
> <AnswerKey>
>      <question id="100">
>           <fragment sequence="3">Some Text</fragment>
>           <fragment sequence="1">Some Text</fragment>
>           <fragment sequence="2">Some Text</fragment>
>     </question>
>
>      <question id="101">
>           <fragment sequence="3">Some Text</fragment>
>           <fragment sequence="2">Some Text</fragment>
>           <fragment sequence="1">Some Text</fragment>
>     </question>
> </AnswerKey>
>
> I need each question element to contain the fragment elements, but
> sorted numerically by sequence.
>
> Here is the XSL I am using:
>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/
> Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
>    <xsl:template match="/">
>          <AnswerKey>
>              <xsl:for-each select="AnswerKey/question">
>                  <xsl:for-each select="fragment">
>              <xsl:sort data-type="text" select="@sequence"/>
>                    <xsl:copy-of select="."/>
>          </xsl:for-each>
>         <xsl:copy-of select="."/>
>              </xsl:for-each>
>            </AnswerKey>
>      </xsl:template>
> </xsl:stylesheet>
>
> I think the problem is the second "copy-of".  I can't seem to get the
> syntax correct for what I am looking to do. Can anyone help?  Thanks!



I was actually able to find out what I did wrong.  Thanks to anyone
that looked at it and tried to help.  Here is a copy of the XSL
stylesheet i use now to accomplish exactly what I want.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/
Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
	<xsl:output omit-xml-declaration="yes" indent="yes"/>
	<xsl:strip-space elements="*"/>


	<xsl:template match="node()|@*">
		<xsl:copy>
			<xsl:apply-templates select="node()|@*"/>
		</xsl:copy>
	</xsl:template>


	<xsl:template match="question">
		<xsl:copy>
			<xsl:copy-of select="@*"/>
			<xsl:apply-templates>
				<xsl:sort select="@sequence" data-type="number"/>
			</xsl:apply-templates>
		</xsl:copy>
	</xsl:template>


</xsl:stylesheet>