It would be good to know that George has used one of the most powerful XSLT 
design pattern -- the identity template and overriding it for a few 
exceptional types of nodes.

Cheers,
Dimitre Novatchev

"George Bina" <george@o...> wrote in message 
news:1160121153.189605.276550@e......
> Hi,
>
> There are many ways you can achieve that, one possibility is below.
> That matches on elements that have at most one ancestor element and
> replaces them with div and by default copies any node to the output.
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> version="1.0">
>    <xsl:template match="*[count(ancestor::*)&lt;2]">
>        <div><xsl:apply-templates/></div>
>    </xsl:template>
>    <xsl:template match="node() | @*">
>        <xsl:copy>
>            <xsl:apply-templates select="node() | @*"/>
>        </xsl:copy>
>    </xsl:template>
> </xsl:stylesheet>
>
> Best Regards,
> George
> ---------------------------------------------------------------------
> George Cristian Bina
> <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
> www.---.com
>
>
>
>
> deepak.programming@g... wrote:
>> Dear All,
>>       I have a problem regarding Xsl Transformation. The Problem is
>> that I want to apply xsl transformation till a level and after that i
>> want that the original structure should be copied as it is. For ex.
>>
>> <node>
>>   <subNode>
>>     <childNode1>
>>      </childNode1>
>>      <childNode2>
>>      </childNode2>
>>   </subNode>
>> </node>
>>  in the above xml only the xsl transformation should apply to node and
>> subnode. After that the transformation should result in same node
>> structure as it is given. somewhat like this
>> <div>  --- replaced node
>>   <div>  -- replace subnode
>>   --structure as it is.
>>   <childNode1>
>>   </childNode1>
>>   <childNode2>
>>   </childNode2>
>>   </div>
>> </div> Can any one tell me how to achieve that. thanks in advance.
>> Deepak.
>