Thanks George. This have solved my problem.
I have used the <xsl:copy></xsl:copy> tags that u have explained for
the same.

George Bina wrote:
> Hi,
>
> There are many ways you can achieve that, one possibility is below.
> That matches on elements that have at most one ancestor element and
> replaces them with div and by default copies any node to the output.
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> version="1.0">
>     <xsl:template match="*[count(ancestor::*)&lt;2]">
>         <div><xsl:apply-templates/></div>
>     </xsl:template>
>     <xsl:template match="node() | @*">
>         <xsl:copy>
>             <xsl:apply-templates select="node() | @*"/>
>         </xsl:copy>
>     </xsl:template>
> </xsl:stylesheet>
>
> Best Regards,
> George
> ---------------------------------------------------------------------
> George Cristian Bina
> <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
> www.---.com
>
>
>
>
> deepak.programming@g... wrote:
> > Dear All,
> >       I have a problem regarding Xsl Transformation. The Problem is
> > that I want to apply xsl transformation till a level and after that i
> > want that the original structure should be copied as it is. For ex.
> >
> > <node>
> >   <subNode>
> >     <childNode1>
> >      </childNode1>
> >      <childNode2>
> >      </childNode2>
> >   </subNode>
> > </node>
> >  in the above xml only the xsl transformation should apply to node and
> > subnode. After that the transformation should result in same node
> > structure as it is given. somewhat like this
> > <div>  --- replaced node
> >   <div>  -- replace subnode
> >   --structure as it is.
> >   <childNode1>
> >   </childNode1>
> >   <childNode2>
> >   </childNode2>
> >   </div>
> > </div> Can any one tell me how to achieve that. thanks in advance.
> > Deepak.