Having looked more closely the xsl:call-template element is not closed 
correctly.

-- 

Joe Fawcett -  XML MVP


http://joe.fawcett.name

"Joe Fawcett" <joefawcett@n...> wrote in message 
news:eIiWhimzGHA.4228@T......
> Can you elaborate? There doesn't seem anything wrong per se with your 
> XSLT.
> What is the input XML and what results do you get that you aren't 
> expecting?
>
> -- 
>
> Joe Fawcett -  XML MVP
>
>
> http://joe.fawcett.name
>
> "Ghena" <lastminutesud@g...> wrote in message 
> news:1157149724.064348.303040@m......
>> sorry my code is:
>>
>> <?xml version="1.0"?>
>> <xsl:stylesheet version="1.0"
>> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>> xmlns:msxsl="urn:schemas-microsoft-com:xslt">
>>
>> <xsl:output method="html" indent="yes"/>
>>
>> <xsl:template match="/">
>> <xsl:call-template name="positionfilter">
>> <xsl:with-param name="sortedlist">
>> <xsl:for-each
>> select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardList/Outward/*"
>>>
>> <xsl:sort select="Price/amount" data-type="number" order="ascending" />
>> <xsl:copy-of select="."/>
>> </xsl:for-each>
>> </xsl:with-param>
>> </xsl:call-template/>
>> </xsl:template>
>>
>>
>> <xsl:template name="positionfilter">
>> <xsl:param name="sortedlist"/>
>> <xsl:for-each select="msxsl:node-set($sortedlist)/*">
>> <xsl:text>test</xsl:text>
>> </xsl:for-each>
>> </xsl:template>
>> </xsl:stylesheet>
>>
>
>