Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: Sort using node-set >Thread Next - Re: Sort using node-set Re: Sort using node-setTo: NULL Date: 9/2/2006 9:20:00 AM Can you elaborate? There doesn't seem anything wrong per se with your XSLT. What is the input XML and what results do you get that you aren't expecting? -- Joe Fawcett - XML MVP http://joe.fawcett.name "Ghena" <lastminutesud@g...> wrote in message news:1157149724.064348.303040@m...... > sorry my code is: > > <?xml version="1.0"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xmlns:msxsl="urn:schemas-microsoft-com:xslt"> > > <xsl:output method="html" indent="yes"/> > > <xsl:template match="/"> > <xsl:call-template name="positionfilter"> > <xsl:with-param name="sortedlist"> > <xsl:for-each > select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardList/Outward/*" >> > <xsl:sort select="Price/amount" data-type="number" order="ascending" /> > <xsl:copy-of select="."/> > </xsl:for-each> > </xsl:with-param> > </xsl:call-template/> > </xsl:template> > > > <xsl:template name="positionfilter"> > <xsl:param name="sortedlist"/> > <xsl:for-each select="msxsl:node-set($sortedlist)/*"> > <xsl:text>test</xsl:text> > </xsl:for-each> > </xsl:template> > </xsl:stylesheet> > | ||||||
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