Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Sort using node-set >Thread Next - Re: Sort using node-set Re: Sort using node-setTo: NULL Date: 9/1/2006 3:29:00 PM sorry my code is: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <xsl:call-template name="positionfilter"> <xsl:with-param name="sortedlist"> <xsl:for-each select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardList/Outward/*" > <xsl:sort select="Price/amount" data-type="number" order="ascending" /> <xsl:copy-of select="."/> </xsl:for-each> </xsl:with-param> </xsl:call-template/> </xsl:template> <xsl:template name="positionfilter"> <xsl:param name="sortedlist"/> <xsl:for-each select="msxsl:node-set($sortedlist)/*"> <xsl:text>test</xsl:text> </xsl:for-each> </xsl:template> </xsl:stylesheet> | ||||||
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