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| | | Altova Mailing List Archivesputting dataTo: NULL Date: 8/1/2006 3:31:00 AM
Hi All,
i have the following xml:
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="Introduce.xsl"?>
<NamedParams Name="Product-Line-Descriptor">
<NamedParams Name="Product-Line">
<NamedParams Name=" BASE v4.0">
<Param Name="ProjectManagerMail" Value="gg@j..."/>
<NamedParams Name="NotifyAddresses">
<Param Name="1" Value="ff@j..."/>
<Param Name="2" Value="yy@j..."/>
</NamedParams>
<Param Name="BasedOn" Value="Gabi"/>
</NamedParams>
</NamedParams>
</NamedParams>
and the following xsl file:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method='html' version='1.0' encoding='UTF-8' indent='yes'/>
<xsl:template match="/">
<HTML>
<HEAD>
<TITLE>Product Line Descriptor</TITLE>
</HEAD>
<h2>PRODUCT LINE DESCRIPTOR </h2>
<BODY>
<table border="2" bgcolor="#FFF000" >
<TR>
<TH> Product Name</TH>
<TH> Project Manager</TH>
<TH> Notify Adress 1</TH>
<TH> Notify Adress 2</TH>
<TH> Based On </TH>
</TR>
<xsl:for-each select="NamedParams/NamedParams/NamedParams">
<tr>
<td>
<xsl:value-of select="@Name"/>
</td>
<td>
<xsl:value-of select="Param/@Value"/>
</td>
<xsl:for-each select="NamedParams/Param">
<td>
<xsl:value-of select="@Value" />
</td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</BODY>
</HTML>
</xsl:template>
</xsl:stylesheet>
my problem is to get the following line:
<Param Name="BasedOn" Value="Gabi"/>
and transfer it to xsl (get the right path)
in my xsl file.
i know that it better to do in template.
if someone can give a sample how should i implement it with template, ill
appriciate it.
Thanks
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