abrahamregisraj@g... wrote:


> <Level1>
   ^^^^^^^

> </level1>
     ^^^^^^

That is not well-formed, if the start tag has element name 'Level1' then 
the end tag needs the same element name and not 'level1'.

And you even want that transformed:

> <Level1 name = "Sample 3 (level1)" description = "This is Sample
    ^^^^^^

> </level1>
    ^^^^^^^

That is not possible.

Assuming you have consistent naming of 'level<n>' then try this stylesheet

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="1.0">

<xsl:output method="xmll" indent="yes" />

<xsl:template match="@* | node()">
   <xsl:copy>
     <xsl:apply-templates select="@* | node()" />
   </xsl:copy>
</xsl:template>

<xsl:template match="*[starts-with(local-name(), 'level')]">
   <xsl:copy>
     <xsl:apply-templates select="name | description" 
mode="element-to-attribute" />
     <xsl:apply-templates select="*[not(self::name) and 
not(self::description)]" />
   </xsl:copy>
</xsl:template>

<xsl:template match="*" mode="element-to-attribute">
   <xsl:attribute name="{name()}" namespace="{namespace-uri()}">
     <xsl:value-of select="." />
   </xsl:attribute>
</xsl:template>

</xsl:stylesheet>


Note however that choosing element names where an index or a level shows 
up in the element names is rather poor design.



-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/