George Bina wrote:

> You can do that with a schema aware XSLT 2.0 processor like Saxon 8 SA
> from Saxonica for instance. See below a working sample.

George is right, XSLT 1.0/XPath 1.0 is not schema aware at all so using 
an XSLT 2.0 schema aware processor is one solution.
However MSXML 4 and later and .NET 2.0 XslCompiledTransform while 
implementing XSLT/XPath 1.0 provide some extension functions to access 
schema type information so with those processors you could do the 
following (using the same schema George has posted):

<xsl:stylesheet version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   xmlns:ms="urn:schemas-microsoft-com:xslt"
   exclude-result-prefixes="ms">


   <xsl:template match="/">
     <result><xsl:apply-templates/></result>
   </xsl:template>

   <!-- Match on any element that has the type person -->
   <xsl:template match="*[ms:type-is('', 'person')]">
     <xsl:copy-of select="."></xsl:copy-of>
   </xsl:template>

</xsl:stylesheet>

Now you need to make sure when the XML is parsed that the schema is 
known, one easy way to do that is to use xsi:noNamespaceSchemaLocation e.g.

<?xml version="1.0" encoding="UTF-8"?>
<test
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:noNamespaceSchemaLocation="test.xsd">
   <father>
     <name>test1</name>
   </father>
   <mother>
     <name>test2</name>
   </mother>
</test>

See the MSXML documentation on using those extension functions here
<http://msdn.microsoft.com/library/default.asp?url=/library/en-us/xmlsdk/html/b1643c25-3f62-4f97-b00a-38026a75db0d.asp>
<http://msdn.microsoft.com/library/default.asp?url=/library/en-us/xmlsdk/html/f1c46829-7149-4957-b789-220b5a0b38ae.asp>

-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/