This is a grouping problem, and is solved best using Muenchian method..

<?xml version="1.0"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
version="1.0">

<xsl:output method="xml" indent="yes" />

<xsl:key name="by-title" match="row" use="@title" />

<xsl:template match="/rows">
  <Titles>
    <xsl:for-each select="row[generate-id() = generate-id(key('by-title', 
@title)[1])]">
      <Title name="{@title}">
        <xsl:copy-of select="key('by-title', @title)" />
      </Title>
    </xsl:for-each>
  </Titles>
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

"donal.conlon" wrote:

> Any one help me convert the following using xsl?  Is it even possible?
> 
> Appreciate any thoughts.
> 
> <rows>
> <row name='item 1' title='Engineer' expertLevel='Master' />
> <row name='item 2' title='Architect' expertLevel='Student' />
> <row name='item 3' title='Engineer' expertLevel='Student' />
> <rows>
> 
> to...
> 
> <Title name="Engineer">
>     <row name='item 1' title='Engineer' expertLevel='Master' />
>     <row name='item 3' title='Engineer' expertLevel='Student' />
> </Title>
> <Title name="Architect">
>     <row name='item 2' title='Architect' expertLevel='Student' />
> </Title>
> 
>