Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: How to match on a literal asterisk [Thread Next] Re: How to match on a literal asteriskTo: NULL Date: 3/7/2006 9:41:00 PM On 7 Mar 2006 08:16:34 -0800, glenn.owens@g... wrote: >Well... the following code, when transformed, yields an unexpected >child error: > ><xsl:when test="contains(Name,'*')"> I'm pretty damn sure there's nothing wrong with that <g> As you're selectively showing us only part of the stylesheet, have you considered posting either the entire <xsl:when /> segment, plus some XML content - or better, both the complete xslt file and a small but complete segment of your XML ? It would save everybody having to guess where your problem lies - as I say I'm sure it's not the above line, maybe you or the xslt processor miscounted the line numbers ? HTH Cheers - Neil | ||||||
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