Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: How to match on a literal asterisk >Thread Next - Re: How to match on a literal asterisk Re: How to match on a literal asteriskTo: NULL Date: 3/7/2006 5:33:00 PM glenn.owens@g... wrote: > the following code, when transformed, yields an unexpected > child error: > > <xsl:when test="contains(Name,'*')"> Which XSLT processor are you using? -- Martin Honnen --- MVP XML http://JavaScript.FAQTs.com/ | ||||||
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