Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: How to match on a literal asterisk >Thread Next - Re: How to match on a literal asterisk Re: How to match on a literal asteriskTo: NULL Date: 3/7/2006 8:17:00 AM Well... the following code, when transformed, yields an unexpected child error: <xsl:when test="contains(Name,'*')"> | ||||||
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