Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: Simple copy of a list in XSL [Thread Next] Re: Simple copy of a list in XSLTo: NULL Date: 3/7/2006 1:14:00 AM Thanks a lot, it works ! Now, i wonder why i didn't see this "copy-of" sooner !!! Thank you George ! Yohan Yohan wrote: > I forgot one thing : i'd like XSL to reproduce the XML elements "ul" > and "li". > Is it what "copy-of" does ? > > George Bina wrote: > > Hi Yohan, > > > > A simple copy-of should copy your list in the result. Here it is a full > > working sample. > > > > XML > > > > <ul> > > <li> item 1 </li> > > <li> item 2 > > <ul> > > <li> item 2.1 </li> > > <li> item 2.1 </li> > > </ul> > > </li> > > <li> item 3 </li> > > </ul> > > > > XSL > > > > <?xml version="1.0" encoding="UTF-8"?> > > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > > version="1.0"> > > <xsl:template match="ul"> > > <xsl:copy-of select="."/> > > </xsl:template> > > </xsl:stylesheet> > > > > Best Regards, > > George > > --------------------------------------------------------------------- > > George Cristian Bina > > <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger > > www.---.com | ||||||
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