Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: Simple copy of a list in XSL >Thread Next - Re: Simple copy of a list in XSL Re: Simple copy of a list in XSLTo: NULL Date: 3/7/2006 12:55:00 AM I forgot one thing : i'd like XSL to reproduce the XML elements "ul" and "li". Is it what "copy-of" does ? George Bina wrote: > Hi Yohan, > > A simple copy-of should copy your list in the result. Here it is a full > working sample. > > XML > > <ul> > <li> item 1 </li> > <li> item 2 > <ul> > <li> item 2.1 </li> > <li> item 2.1 </li> > </ul> > </li> > <li> item 3 </li> > </ul> > > XSL > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="1.0"> > <xsl:template match="ul"> > <xsl:copy-of select="."/> > </xsl:template> > </xsl:stylesheet> > > Best Regards, > George > --------------------------------------------------------------------- > George Cristian Bina > <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger > www.---.com | ||||||
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