42 wrote:
> Hi,
> I'm pretty new to XSL, and I've bumped into what is probably (hopefully) 
> a simple problem.
> 
> I need to convert a simple xml document containing just repeated 
> 'generic' data blocks of:
> 
> <record>
> 	<data>Bob</data>
> 	<data>Smith</data>
> 	...
> </record>
> 
> to:
> 
> <person>
> 	<firstname>Bob</firstname>
> 	<lastname>Smith</lastname>
> 	...
> </person>
> 
> The source xml contains the same number of  <data> elements for each 
> record, are in a consistent order, with no omissions.
> 
> I've figured out how to use foreach to iterate over the person records, 

Don't. Use templates instead, it's faster and clearer.

<xsl:template match="record">
   <person>
     <xsl:apply-templates/>
   </person>
</xsl:template>

<xsl:template match="data[1]">
   <firstname>
     <xsl:apply-templates/>
   </firstname>
</xsl:template>

<xsl:template match="data[2]">
   <surname>
     <xsl:apply-templates/>
   </surname>
</xsl:template>

Keep for-each for things like sorting and accessing nodes out of
document order.

> but can't see how to select the nth occurence of <data> within each 
> record.

Think like a tree, not like a chainsaw :-)

///Peter
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