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Re: XSL Problem

From: "Joe Fawcett" <joefawcett@---------.------>
To: NULL
Date: 2/3/2006 8:53:00 AM
"infiniti" <jainamber@g...> wrote in message 
news:1138903520.888282.47800@g......
> HI Joe, thanks for your help. I tried both the changes one by one but I
> was not able to get the "Searches" attribute value with either of them.
> Am I doing something  wrong?
>
Although Anthony's solution using keys is more elegant your XPath to reach 
searches was missing a step:

<xsl:variable name="node" select="/xml/RelatedKeyword/Common[. = 
current()/@searchTerm]" />
<xsl:attribute name="Searches">
<xsl:value-of select="$node/../Searches" /><!-- Searches is a sibling of 
Common so you need to up one level -->
</xsl:attribute>


The complete sheet:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:apply-templates select="xml" />
</xsl:template>
<xsl:variable name="basename" select='bid' />
<xsl:template match="xml">
<xml>
<xsl:for-each select="GetMarketStateResponse">
<row>
<xsl:attribute name="RelatedKeyword">
<xsl:value-of select="@searchTerm" />
</xsl:attribute>
<xsl:variable name="node"
select="/xml/RelatedKeyword/Common[. = current()/@searchTerm]" />
<xsl:attribute name="Searches">
<xsl:value-of select="$node/../Searches" />
</xsl:attribute>
<xsl:for-each select="./Listing">
<xsl:variable name="rank" select="@rank" />
<xsl:attribute name="bid{$rank}">
<xsl:value-of select="@bid" />
</xsl:attribute>
</xsl:for-each>
</row>
</xsl:for-each>
</xml>
</xsl:template>
</xsl:stylesheet>


-- 

Joe Fawcett -  XML MVP

https://mvp.support.microsoft.com/profile=8AA9D5F5-E1C2-44C7-BCE8-8741D22D17A5 




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